Question

如果选择== 1：在def mainmenu（）下我得到这个无效语法：不明白为什么我收到此错误。请帮我解决这个问题。我完全没有理由为什么它在那里。 contacts = {}

class person:

    def ___init__(self,first,last,number):
        self.first = first
        self.last = last
        self.number = number

    def get_info(self):
        print(first,last,number)

class friend(person):

    def __init__(self,email,bday):
        self.email = email
        self.bday = bday

    def get_info_friend(self):
        super().get_info()
        print(email,bday)

def add_a_contact():
    choice  = int(input("Contact type: \n\t 2: Person \nEnter an option here:"))
    first = input("Enter the first name:")
    last = input("Enter the last name:")
    number = input("Enther the number:")

    if choice == 1:
       email = input("Email Address is:")
       bday = input("Their bday is:")
       return Friend(email,bday,first,last,number)
     return person(first,last,number)

def add_contact_to_dict():
    contact = add_a_contact()
    contacts[contact.last_name] = contact

def lookup():
   last = input("What is their last name?:")
   if last in contacts:
        contact = contacts[last]
        print("Name&number: ", contact.first,contact.last,contact.number)
   if type(friend) is friend:
        print("Email and Bday is: ", contact.email,contact.bday)

def mainmenu():
   selection = 0
   temp = ""
   while selection != 3:
       print("Select an option: \n\t 1: Add \n\t 2: Lookup \n\t 3: Exit")
       selection = int(input("Enter an option:")
       if selection == 1:
            temp = add_contact_to_dict()
        elif selection == 2:
            lookup()
        elif selection == 3:
            pass
        else:
            print("Not a valid option")

 if __name__ == "__mainmenu__":
     mainmenu()

Answer 1

因此，当您被要求输入选择时，您需要另一个括号来表示“int”部分。希望这可以解决您的问题。

Def mainmenu下的Python无效语法

1 个答案: