Question

我正在玩Django中的文件上传，但是我收到了这个错误：

Traceback:
File "/Library/Python/2.7/site-packages/django/core/handlers/base.py" in get_response
  111.                     response = wrapped_callback(request, *callback_args, **callback_kwargs)
File "/Users/bli1/Development/Django/TrinityTaaS/parser/views.py" in handle_uploaded_file
  35.     f = open(log_file, "r")

Exception Type: TypeError at /parser/events/
Exception Value: coercing to Unicode: need string or buffer, WSGIRequest found

我不确定如何解决这个问题。

views.py

def handle_uploaded_file(log_file):
    print "HI"
    json_beacons = []
    f = open(log_file, "r")
    # log regex for events
    beacon1 = re.compile(r'.*\[DataCapture\]\s+(?P<beacon_var>\[(.*)\])')
    beacon2 = re.compile(r'.*\[DataCapture\]\s+Event:\s+\{.*\}(?P<beacon_var>\{.*\})')
    for chunk in f.chunk():
        log_entry = re.search(beacon1, chunk)
        if log_entry:
            beacon_json = log_entry.group("beacon_var")
            json_beacons.append(beacon_json[1:-1])
    return json_beacons

def upload_file(request):
    if request.method == "POST":
        form = UploadFileForm(request.POST, request.FILES)
        if form.is_valid():
            json_beacons = handle_uploaded_file(request.FILES['file'])
            return HttpResponseRedirect('/success/')
    else:
        form = UploadFileForm()
    return render_to_response('upload.html', {'form': form})

forms.py

class UploadFileForm(forms.Form):
    title = forms.CharField(max_length=50)
    file = forms.FileField()

Answer 1

由于错误表明log_file是一个响应对象，我猜您实际上是在网址配置中引用handle_uploaded_file而不是upload_file。

Answer 2

除了SmileyChris提到的可能不正确的url配置外，open还需要一个包含文件路径的字符串，而request.FILES包含表示此处记录的文件的对象：https://docs.djangoproject.com/en/dev/ref/files/uploads/#uploaded-files < / p>

您无需open上传的文件，只需使用其read或chunks方法即可获取上传的内容。

在Django中使用文件上载强制转换为Unicode

2 个答案: