Question

保存或读取文件，出了什么问题？

这会创建空文件。

我很困惑，请告诉我如何正确地做到这一点。正如你所看到的，我试图保存一个类然后再读回它们的数组。

public void savePlayers()
{
    string path = @"scores.dat";

    if (File.Exists(path))
    {
        File.Delete(path);
    }

    try
    {
        using (FileStream fs = File.Create(path))
        {
            BinaryFormatter formatter = new BinaryFormatter();
            formatter.Serialize(fs, player.players);
            fs.Close();
        }
    }
    catch
    {
        MessageBox.Show("Failed to save data", "Error", MessageBoxButtons.OK, MessageBoxIcon.Error);
    }
}

public void readPlayers()
{
    string path = @"scores.dat";

    player.players.Clear();
    try
    {
        using (FileStream fs = File.OpenRead(path))
        {
            BinaryFormatter formatter = new BinaryFormatter();
            player.players.Add((Player)formatter.Deserialize(fs));
            fs.Close();
        }
    }
    catch
    {
        MessageBox.Show("Failed to read stats file", "Error", MessageBoxButtons.OK, MessageBoxIcon.Error);
    }
}

Answer 1

您正在保存player.players集合，并且您正在尝试加载单个播放器（player.players.Add((Player)formatter.Deserialize(fs));）。这是不正确的。

这取决于您必须在装载侧（反序列化）或保存侧（序列化）修复此问题。

// Saving
BinaryFormatter formatter = new BinaryFormatter();
formatter.Serialize(fs, player.players.Count); // or Count(), Length, depends on your list, collection,...
for each (Player pl in player.players)
{
  formatter.Serialize(fs, pl);
}
fs.Close();

// Loading
BinaryFormatter formatter = new BinaryFormatter();
int count = (Int32) formatter.Deserialize(fs);
for (int i = 0; i < count; i++)
{
  player.players.Add((Player)formatter.Deserialize(fs));
}
fs.Close();

并且Player类必须标记为[Serializable]，请检查它是否具有此属性。

C＃文件不会保存

1 个答案: