Question

我无法解决这个问题。

这是我目前的输出：

['Direct General Auto Insurance', 'IT Project Manager', 'Nashville', 'TN', '(615) 331-7540']
['Direct General Auto Insurance', 'IT Systems Manager', 'Nashville', 'TN', '(615) 340-6291']
['Direct General Auto Insurance', 'Junior web Developer', 'Nashville', 'TN', '(615) 399-4700']
['Grand Slam Universal, LLC', 'IT Specialist', 'Nashville', 'TN', '(615) 457-3516']
['Ingram Content Group', 'Desktop Engineer', 'La Vergne', 'TN', '(615) 793-5000']
['Direct General Auto Insurance', 'Data Scientist', 'Nashville', 'TN', '(615) 726-3091']
['Direct General Auto Insurance', 'Janitor', 'Nashville', 'TN', '(615) 831-2600']

标题为FIRMNAME, JOBTITLE, CITY, STATE, NUMBER。

对于相同的FIRMNAME我需要同一行中的所有对应JOBTITLE。因此，如果FIRMNAME匹配，则将相应的JOBTITLE添加到该行。

所以输出看起来像这样：

['Direct General Auto Insurance', 'IT Project Manager, IT Systems Manager, Junior Web Developer, Data Scientist, Janitor', 'Nashville', 'TN', '(615) 331-7540']
['Grand Slam Universal, LLC', 'IT Specialist', 'Nashville', 'TN', '(615) 457-3516']
['Ingram Content Group', 'Desktop Engineer', 'La Vergne', 'TN', '(615) 793-5000']

如果列表中已经存在匹配的.insert()，我尝试使用FIRMNAME进行循环，但是无法弄清楚逻辑。

感谢您的帮助。

修改：

这是所需的输出：

['Direct General Auto Insurance', 'IT Project Manager, IT Systems Manager, Junior Web Developer, Data Scientist, Janitor', 'Nashville', 'TN', '(615) 331-7540']
['Direct General Auto Insurance', 'IT Project Manager, IT Systems Manager, Junior Web Developer, Data Scientist, Janitor', 'Nashville', 'TN', '(615) 340-6291']
['Direct General Auto Insurance', 'IT Project Manager, IT Systems Manager, Junior Web Developer, Data Scientist, Janitor', 'Nashville', 'TN', '(615) 399-4700']
['Direct General Auto Insurance', 'IT Project Manager, IT Systems Manager, Junior Web Developer, Data Scientist, Janitor', 'Nashville', 'TN', '(615) 726-3091']
['Direct General Auto Insurance', 'IT Project Manager, IT Systems Manager, Junior Web Developer, Data Scientist, Janitor', 'Nashville', 'TN', '(615) 831-2600']
['Grand Slam Universal, LLC', 'IT Specialist', 'Nashville', 'TN', '(615) 457-3516']
['Ingram Content Group', 'Desktop Engineer', 'La Vergne', 'TN', '(615) 793-5000']

我想保留所有数字。

Answer 1

使用dict索引表格。对于每一行，请检查您是否已经看过该公司并在那里进行插入。如果您需要变得更复杂（例如，具有不同位置的同一公司），则索引键可以成为唯一信息的元组。

my_list = [
    ['Direct General Auto Insurance', 'IT Project Manager', 'Nashville', 'TN', '(615) 331-7540'],
    ['Direct General Auto Insurance', 'IT Systems Manager', 'Nashville', 'TN', '(615) 340-6291'],
    ['Direct General Auto Insurance', 'Junior web Developer', 'Nashville', 'TN', '(615) 399-4700'],
    ['Grand Slam Universal, LLC', 'IT Specialist', 'Nashville', 'TN', '(615) 457-3516'],
    ['Ingram Content Group', 'Desktop Engineer', 'La Vergne', 'TN', '(615) 793-5000'],
    ['Direct General Auto Insurance', 'Data Scientist', 'Nashville', 'TN', '(615) 726-3091'],
    ['Direct General Auto Insurance', 'Janitor', 'Nashville', 'TN', '(615) 831-2600'],
]

index = {}

for item in my_list:
    existing = index.get(item[0])
    if not existing:
        index[item[0]] = item
        # or this, if you want don't want to modify the existing table
        # index[item[0]] = item[:]
    else:
        existing.insert(1, item[1])

for item in sorted(index.values()):
    print item

修改

您的编辑结果完全不同 - 您希望将所有作业插入到公司的每个原始条目中。在这种情况下，我们只需要建立每个公司的工作列表，然后返回到原始列表并插入它们。

import collections my_list = [ ['Direct General Auto Insurance', 'IT Project Manager', 'Nashville', 'TN', '(615) 331-7540'], ['Direct General Auto Insurance', 'IT Systems Manager', 'Nashville', 'TN', '(615) 340-6291'], ['Direct General Auto Insurance', 'Junior web Developer', 'Nashville', 'TN', '(615) 399-4700'], ['Grand Slam Universal, LLC', 'IT Specialist', 'Nashville', 'TN', '(615) 457-3516'], ['Ingram Content Group', 'Desktop Engineer', 'La Vergne', 'TN', '(615) 793-5000'], ['Direct General Auto Insurance', 'Data Scientist', 'Nashville', 'TN', '(615) 726-3091'], ['Direct General Auto Insurance', 'Janitor', 'Nashville', 'TN', '(615) 831-2600'], ] index = collections.defaultdict(list) # generate list of jobs per firm for item in my_list: index[item[0]].append(item[1]) # insert into existing table for item in my_list: del item[1] item[1:2] = index[item[0]] for item my_list: print item

如果某个其他元素匹配，则将一个列表的元素插入到另一个列表中

1 个答案: