Question

我正在尝试在php中制作出勤图表。我希望通过单击单选按钮增加数据库中的出勤计数器。我如何检索值，然后为每个“是”增加？

我需要将更新代码放在下一页吗？

我试着这样..但是这些字段没有得到更新..

if($class=="cse")
    {
        $result = mysqli_query($con, "SELECT * FROM cse");
        echo "<table border=15px cellspacing=40>";
        echo "<tr><th>NAME</th><th>BUPIN</th><th>ATTENDANCE</th></tr>";
        while ($row = mysqli_fetch_array($result)) 
    {
        echo "<tr><td>" . $row["name"] . "</td>" . "<td>" . $row["bupin"] . "</td>";
        echo "<td>" . "<input type='radio' name='presence[".$row["bupin"]."]' value='yes'>Yes";
        echo "<input type='radio' name='presence[".$row["bupin"]."]' value='no'>No" . "</td></tr>";
    }
    echo "</table>";
    ?>
    <html>
    <form action= "final6.php" method="POST">
    <input type="Submit" value="Submit">
    </form>
    </html>
    }}

，下一页代码为：if (isset($_POST["presence"])) { foreach ($presence as $key => $val) { if ($val == 'yes') { $sql = "UPDATE cse SET 1attendance = 1attendance + 1 WHERE bupin = " .$key; msyqli_query($con, $sql); } } } echo "Attendance marked successfully.."; }

我错在哪里？

Answer 1

如果bupin是表cse中的主键（id），那么试试这个。当然，请将查询中的field更改为您要填写的内容。

$result = mysqli_query($con, "SELECT * FROM cse");
echo "<table border=15px cellspacing=40>";
echo "<tr><th>NAME</th><th>BUPIN</th><th>ATTENDANCE</th></tr>";
while ($row = mysqli_fetch_array($result)) {
    echo "<tr><td>" . $row["name"] . "</td>" . "<td>" . $row["bupin"] . "</td>";
    echo "<td>" . "<input type='radio' name='presence[".$row["bupin"]."]' value='yes'>Yes";
    echo "<input type='radio' name='presence[".$row["bupin"]."]' value='no'>No" . "</td></tr>";
}
echo "</table>";


if (isset($_POST["presence"])) {
    foreach ($presence as $key => $val) {
        if ($val == 'yes') {
            $sql = "UPDATE cse SET field = field + 1 WHERE bupin = " . $key;
            msyqli_query($con, $sql);
        }
    }
}

如何在从数据库检索的表中使用单选按钮并将值存储在另一个表中

1 个答案: