Question

我是一个蟒蛇新手并且遇到以下问题。如果我取消注释此代码的最后一行：

# traverse all directories
for root, dirs, files in os.walk(args.rootfolder):
    for file in files:
        print('Current file name: ' + file)
        if file.endswith('.savx'):
            # read single xml savx file
            currfilename = os.path.join(root,file)
            print('Current full file name: ' + currfilename)
            tree = ET.parse(currfilename)
            # root = tree.getroot() <-- if I uncomment this line I get errors

我收到此错误：

Traceback (most recent call last):
  File "convert.py", line 30, in <module>
    currfilename = os.path.join(root,file)
  File "C:\progs\develop\Python34\lib\ntpath.py", line 108, in join
    result_drive, result_path = splitdrive(path)
  File "C:\progs\develop\Python34\lib\ntpath.py", line 161, in splitdrive
    normp = p.replace(_get_altsep(p), sep)
AttributeError: 'xml.etree.ElementTree.Element' object has no attribute 'replace'

看起来错误出现在第二次file in files循环迭代之后。

Answer 1

您在代码中使用root两次，用于不同的事情：

for root, dirs, files in os.walk(args.rootfolder):
#   ^^^^

和

root = tree.getroot()

因此，在构建要加载的下一个文件名时，尝试使用root作为路径字符串：

currfilename = os.path.join(root,file)

您会发现您使用ElementTree对象替换了root路径名称。

为根目录名称或ElementTree对象使用不同的名称。例如，使用dirname：

for dirname, dirs, files in os.walk(args.rootfolder):
    for file in files:
        print('Current file name: ' + file)
        if file.endswith('.savx'):
            # read single xml savx file
            currfilename = os.path.join(dirname, file)
            print('Current full file name: ' + currfilename)
            tree = ET.parse(currfilename)
            root = tree.getroot()

使用ElementTree时，Object没有属性错误

1 个答案: