Question

我需要遍历myn表，在每行中检查其中一列（ id ），并在另一个表中匹配这些 id 值以获取来自它的价值称为 useragent 。

但是我的while循环当前有问题，这只会检查第一行的 id 值（它不会继续检查每一行）

$myarray = mysql_query("SELECT * FROM table_105");

while($row = mysql_fetch_array($myarray)){
    $table = 'table_105';
    $update = mysql_query("SELECT id as unp FROM $table");
    $col = mysql_fetch_assoc($update);
    $col_id = ($col["unp"]);

    $var1 = mysql_query("SELECT useragent as ua FROM paneltb WHERE id = $col_id");
    $col3 = mysql_fetch_assoc($var1);
    $col_ua = ($col3["ua"]);

    $browser = get_browser($col_ua, true);
    $platform = $browser['platform'];
    $device_name = $browser['device_name'];
    $browser_name = $browser['browser'];
    $version = $browser['version'];

    mysql_query("
            INSERT INTO table_tester(`trackerID`,`id`, `timestamp`, `useragent_browser`,`useragent_OS`,`useragent`)
            SELECT `trackerID`, `id`, `timestamp`, `useragent_browser`, `useragent_OS`,'".$col3["ua"]."'
            FROM $table")
            or die(mysql_error());

}

Answer 1

因为你的代码只有一行，如果你想检查所有行然后将你的内容放在内部，而循环中的id和useragent如下：

$myarray = mysql_query("SELECT * FROM table_105");
while($row = mysql_fetch_array($myarray)){
$table = 'tracktable_105';
$update = mysql_query("SELECT id as unp FROM $table");
while($col = mysql_fetch_assoc($update))
{
$col_id = ($col["unp"]);

$var1 = mysql_query("SELECT useragent as ua FROM paneltb WHERE id = $col_id");
while($col3 = mysql_fetch_assoc($var1))
{
$col_ua = $col3["ua"];

$browser = get_browser($col_ua, true);
$platform = $browser['platform'];
$device_name = $browser['device_name'];
$browser_name = $browser['browser'];
$version = $browser['version'];
mysql_query("
        INSERT INTO table_tester(`trackerID`,`id`,`timestamp`,`useragent_browser`,`useragent_OS`,`useragent`) SELECT `trackerID`, `id`, `timestamp`, `useragent_browser`, `useragent_OS`,'".$col3["ua"]."' FROM $table") or die(mysql_error());
}
}
}

为什么我的PHP代码不检查所需MYSQL表的每一行

1 个答案: