Question

SELECT ru.roleuser ,
opr.emplid ,
ru.rolename ,
ru.dynamic_sw ,
AU.AUDIT_OPRID ,
TO_CHAR(au.audit_stamp , 'YYYY-MM-DD  HH.MI.SS')
FROM psoprdefn opr ,
psroleuser ru
LEFT OUTER JOIN HRSECADM.wb_audit_psroleuser AU
ON (au.roleuser     = ru.roleuser
AND au.rolename     = ru.rolename )
WHERE opr.oprid     = ru.roleuser
AND (au.audit_stamp =
(SELECT MAX(au_ed.audit_stamp)
FROM HRSECADM.wb_audit_psroleuser au_ed
WHERE ru.roleuser  = au_ed.roleuser
AND au_ed.rolename = ru.rolename
)
OR au.audit_stamp IS NULL) ;

获取错误：

ORA-01779: cannot modify a column which maps to a non key-preserved table.

我在上面的sql.if中面临上述问题我希望在上面的sql上更新数据我们面临一些sql错误。错误位置：30返回：1779 - ORA-01779: cannot modify a column which maps to a non key-preserved table SQL stmt失败：UPDATE PS_ROLUSR_AUD_VW_W SET OPRID =：1 WHERE OPRID =：2 AND EMPLID =：3

Answer 1

您正在尝试访问PeopleSoft DataDictionary表以执行某些更新。那太热了！但是，您的SQL是两个表之间的连接。在Oracle中，通常允许更新连接，但有几个条件：

更新仅影响其中一个基表
其他表必须是“密钥保留”，表示每个表它们必须在上面的基表中有一行。

Answer 2

确保用于加入的表格应该有一些密钥。

DROP TABLE x;

CREATE TABLE x
(
   child    NUMBER (1),                                        -- primary key,
   parent   NUMBER (3),
   notes    VARCHAR2 (10),
   notes1   VARCHAR2 (10),
   notes2   VARCHAR2 (10),
   notes3   VARCHAR2 (10),
   notes4   VARCHAR2 (10)
);

CREATE TABLE y (child NUMBER (1) PRIMARY KEY);

INSERT INTO x
     VALUES (1,
             NULL,
             NULL,
             NULL,
             NULL,
             NULL,
             NULL);

INSERT INTO x
     VALUES (2,
             1,
             NULL,
             NULL,
             NULL,
             NULL,
             NULL);

INSERT INTO x
     VALUES (3,
             1,
             NULL,
             NULL,
             NULL,
             NULL,
             NULL);

INSERT INTO x
     VALUES (4,
             2,
             NULL,
             NULL,
             NULL,
             NULL,
             NULL);

INSERT INTO x
     VALUES (5,
             1,
             NULL,
             NULL,
             NULL,
             NULL,
             NULL);

INSERT INTO x
     VALUES (5,
             NULL,
             NULL,
             NULL,
             NULL,
             NULL,
             NULL);

INSERT INTO x
     VALUES (6,
             5,
             NULL,
             NULL,
             NULL,
             NULL,
             NULL);

INSERT INTO x
     VALUES (7,
             5,
             NULL,
             NULL,
             NULL,
             NULL,
             NULL);

INSERT INTO x
     VALUES (8,
             6,
             NULL,
             NULL,
             NULL,
             NULL,
             NULL);

INSERT INTO y
     VALUES (1);

INSERT INTO y
     VALUES (2);

INSERT INTO y
     VALUES (5);

INSERT INTO y
     VALUES (6);

SELECT * FROM x;

UPDATE (SELECT x.child,
               x.parent,
               x.notes,
               x.notes1,
               x.notes2,
               x.notes3,
               x.notes4
          FROM x INNER JOIN y ON x.parent = y.child
         WHERE     TRIM (notes) IS NULL
               AND TRIM (notes1) IS NULL
               AND TRIM (notes2) IS NULL
               AND TRIM (notes3) IS NULL
               AND TRIM (notes4) IS NULL) z
   SET z.notes1 = 'notes1',
       z.notes2 = 'notes2',
       z.notes3 = 'notes3',
       z.notes4 = 'notes4';

无法修改映射到非密钥保留表的列

2 个答案: