Question

我有一个UISearchDisplaycontroller，我必须将信息推送到文本字段，并需要将其链接到导航视图控制器。

这是我的代码 -

- (void)prepareForSegue:(UIStoryboardSegue *)segue sender:(id)sender {
if ([segue.identifier isEqualToString:@"showRecipeDetail"]) {
    NSIndexPath *indexPath = nil;
    Recipe *recipe = nil;

    if (self.searchDisplayController.active) {
        indexPath = [self.searchDisplayController.searchResultsTableView indexPathForSelectedRow];
        recipe = [searchResults objectAtIndex:indexPath.row];
    } else {
        indexPath = [self.tableView indexPathForSelectedRow];
        recipe = [recipes objectAtIndex:indexPath.row];
    }

    RecipeDetailViewController *destViewController = segue.destinationViewController;
    destViewController.recipe = recipe;



}

}

Answer 1

您的UINavigationController层次结构错误或错误放置。

Plz参考

http://developer.apple.com/library/ios/#documentation/uikit/reference/UINavigationController_Class/Reference/Reference.html

将数据从UITableViewCell推送到UINavigationController

1 个答案: