Question

我似乎无法输出我需要的文本文件。基本上我必须从文本文件和他们的分数中选择保龄球，并输出他们的名字，他们的分数，如果它是“完美”“高于平均水平”或“低于平均水平”这是我的代码到目前为止。

bowler_scores = {}
infile = open('bowlingscores.txt', 'r')
for line in infile:
    if line.strip().isalpha():
        names = line.strip()
    elif line.strip().isdigit():
        scores = int(line)
        bowler_scores[names] = scores
total = sum(bowler_scores.values())
num_scores = len(bowler_scores.values())
def my_avg(x, y):
    average = float(x/y)
    return average
my_avg(total, num_scores)
infile.close()

outfile = open('output.txt', 'w')
for x, y in bowler_scores.items():
    a = str(x)
    b = str(y)
    if y == 300:
        outfile.write('{} {} Perfect/n'.format(a, b))
    elif y > my_avg(total, num_scores):
        outfile.write('{} {} Above average'.format(a, b))
    elif y < my_avg(total, num_scores):
        outfile.write('{} {} Below average'.format(a, b))

我无法弄清楚如何将答案打印到另一个文本文件中。我见过有人询问同样的问题，但在答案中他们只是打印出来而不是将其输出到文本文件中。请帮忙吗？

Answer 1

bowler_scores = {}
for line in open('bowlingscores.txt', 'rb'):
    line = line.strip()
    if line.isalpha():
        name = line.strip()
        bowler_scores[name] = [] #1
    elif line.isdigit():
        score = int(line)
        bowler_scores[name].append(score) #2

def avg(x, y):
    return x/float(y) 

total = sum([sum(scores) for scores in bowler_scores.values()]) #3
num_scores = sum(len(value) for value in bowler_scores.values()) #4
total_avg = avg(total, num_scores) # 5

output = open('output.txt','wb')
for name, scores in bowler_scores.items(): #6
    bowler_avg = avg(sum(scores),len(scores)) #7
    if sum(scores) == 60: 
        output.write('{0} {1} Perfect\r\n'.format(name, scores))
    elif bowler_avg > total_avg: #8
        output.write('{} {} Above average\r\n'.format(name, scores)) #9
    elif bowler_avg < total_avg:
        output.write('{} {} Below average\r\n'.format(name, scores))
output.close()

您的代码存在一些小问题：

首先必须在dict中创建一个圆形清单，并带有一个空列表你将把分数放在哪里
然后将分数附加到此列表
要计算我使用list compression的总数，我将每个投球手的得分相加，然后将它们的总和相加。
还使用列表压缩来计算分数大小
您可以在变量中指定avg以再次重复使用
使用更具描述性的名称
计算投球手得分的平均值
检查平均值是否大于或低于平均值
您可以直接使用这些项目，它们将被转换为字符串，无需使用str（）

如果每个玩家只有一个分数，那么代码就是：

for line in open('bowlingscores.txt', 'rb'):
    line = line.strip()
    if line.isalpha():
        name = line.strip()
    elif line.isdigit():
        score = int(line)
        bowler_scores[name] = score

...

total = sum(bowler_scores.values())
num_scores = len(bowler_scores.values())

...

output = open('output.txt','wb')
for name, score in bowler_scores.items():
    if score == 300:
       output.write('{0} {1} Perfect\r\n'.format(name, score))
    elif score > total_avg:  #8
        output.write('{} {} Above average\r\n'.format(name, score))
    elif score < total_avg:
        output.write('{} {} Below average\r\n'.format(name, score))
output.close()

无法输出文本文件的答案

1 个答案: