我有一个字符串,我用C ++使用Crypto ++加密以下mehtod:
std::ifstream t(filename); //File to be encrypt
std::stringstream buffer;
buffer << t.rdbuf();
ofstream combined_file2(filename2); //Encrypted file
combined_file2 << encrypt(buffer.str());
string encrypt(string data)
{
// Key and IV setup
std::string key = "0123456789abcdef";
std::string iv = "aaaaaaaaaaaaaaaa";
//Alternative
//byte key[CryptoPP::AES::DEFAULT_KEYLENGTH], iv[CryptoPP::AES::BLOCKSIZE];
//memset(key, 0x00, CryptoPP::AES::DEFAULT_KEYLENGTH);
//memset(iv, 0x00, CryptoPP::AES::BLOCKSIZE);
std::string plaintext = data;
std::string ciphertext;
// Create Cipher Text
CryptoPP::AES::Encryption aesEncryption((byte *)key.c_str(), CryptoPP::AES::DEFAULT_KEYLENGTH);
CryptoPP::CBC_Mode_ExternalCipher::Encryption cbcEncryption(aesEncryption, (byte *)iv.c_str());
//Alternative
//CryptoPP::AES::Encryption aesEncryption(key, CryptoPP::AES::DEFAULT_KEYLENGTH);
//CryptoPP::CBC_Mode_ExternalCipher::Encryption cbcEncryption(aesEncryption, iv);
CryptoPP::StreamTransformationFilter stfEncryptor(cbcEncryption, new CryptoPP::StringSink(ciphertext));
stfEncryptor.Put(reinterpret_cast<const unsigned char*>(plaintext.c_str()), plaintext.length() + 1);
stfEncryptor.MessageEnd();
return ciphertext;
}
当我尝试在我的C#应用程序中解密文件时,我收到消息,数据的长度无效。我认为字节数组的长度不是16的倍数,所以我得到了错误。我尝试使用填充,但它无法正常工作。
以下是我解密文件的方法:
string plaintext = Decrypt(File.ReadAllBytes(path));
private static string Decrypt(byte[] cipherText)
{
if (cipherText == null || cipherText.Length <= 0)
throw new ArgumentNullException("cipherText");
byte[] Key = GetBytes(ConfigurationManager.AppSettings["aes_key"]);
byte[] IV = GetBytes(ConfigurationManager.AppSettings["aes_iv"]);
// Declare the string used to hold the decrypted text.
string plaintext = null;
// Create an RijndaelManaged object with the specified key and IV.
using (RijndaelManaged rijAlg = new RijndaelManaged())
{
rijAlg.Key = Key;
//rijAlg.IV = IV;
//for testing
rijAlg.IV = new byte[] { 97, 97, 97, 97, 97, 97, 97, 97, 97, 97, 97, 97, 97, 97, 97, 97 };
// Create a decrytor to perform the stream transform.
ICryptoTransform decryptor = rijAlg.CreateDecryptor(rijAlg.Key, rijAlg.IV);
// Create the streams used for decryption.
using (MemoryStream msDecrypt = new MemoryStream(cipherText))
{
using (CryptoStream csDecrypt = new CryptoStream(msDecrypt, decryptor, CryptoStreamMode.Read))
{
using (StreamReader srDecrypt = new StreamReader(csDecrypt))
{
// Read the decrypted bytes from the decrypting stream
// and place them in a string.
plaintext = srDecrypt.ReadToEnd();
}
}
}
}
return plaintext;
}
我该如何解决这个问题?是否有任何功能来填充,或者填充是错误的方法?
答案 0 :(得分:0)
基于评论:
在C ++中,我保存了一个文件combined_file2&lt;&lt;加密(buffer.str());我 读入我的C#程序字符串plaintext = 解密(File.ReadAllBytes(路径));
我认为嵌入式NULL不会导致encrypt
函数出现问题,因为它返回string
,并且包含明确的长度。
但是,嵌入式NULL以及在C ++中将文件写入磁盘的方式(或从C#中的磁盘读取)将是一个问题,因为这将在第一个嵌入的NULL停止:combined_file2 << encrypt(buffer.str())
。
也许以下内容会有所帮助:
StringSource ss(ciphertext, true /*pumpAll*/);
FileSink fs("my-encrypted-file.bin", true /*binary*/);
ss.TransferTo(fs);
如果您使用的是C ++流,那么请在流对象上使用write
方法:
ofstream combined_file2;
...
combined_file2.write(ciphertext.data(), ciphertext.size());