Question

 [HttpPost]
        public ActionResult Create(EmployeeEntry employeeentry)
        {
            if (ModelState.IsValid)
            {
                EmployeeEntry employeesales = new EmployeeEntry();
                employeesales.stock_id = employeeentry.stock_id;
                employeesales.quantity = employeeentry.quantity;
                employeesales.total = employeeentry.total;
                employeesales.employeeid = (int)TempData["Name"];

                db.EmployeeEntries.Add(employeesales);
                db.SaveChanges();
                return RedirectToAction("Index");
            }

            ViewBag.stock_id = new SelectList(db.AddProduct, "stock_id", "Product_name", employeeentry.stock_id);
            return View(employeeentry);
        }

这是我的代码，我在将TempData转换为integer时遇到错误.TempData [＆＃34; Name＆＃34;]包含已登录的员工的ID。

 var Result = from a in db.login where a.userName == login.userName && a.Password == login.Password select a.login_id;
                    TempData["Name"] = Result.Single();

                    return RedirectToAction("Index", "EmployeeHome");

我理解TempData [＆＃34;名称＆＃34;]没有价值。我如何解决这个问题。

Answer 1

TempData用于将数据从当前请求传递到后续请求（意味着从一个页面重定向到另一个页面）。

因此，在您的情况下，Tempdata [“Name”]仅在EmployeeHome Controller的当前操作和Index操作中可用。

所以你需要Session [“Name”]代替Tempdata [“Name”]

赞：

var Result = from a in db.login where a.userName == login.userName && 
             a.Password == login.Password select a.login_id;
Session["Name"] = Result.Single();
return RedirectToAction("Index", "EmployeeHome");

和其他行动

[HttpPost]
    public ActionResult Create(EmployeeEntry employeeentry)
    {
    …
    employeesales.employeeid = (int)Session["Name"];

对象引用未设置为TempData中对象的实例

1 个答案: