Question

我知道这个问题是一个血腥的初学者问的问题，但任何人都可以像看待这段代码那样善良：

SELECT w.word 
FROM words
AS w
INNER JOIN words as w1 ON w.meaning=w1.meaning
AND w1.word='word1'

表格如下：

id meaning word
 1       1 word1
 2       1 word2
 3       1 word3
 4       2 word4
 5       2 word5
 6       3 word6

上面的代码给出了结果Violine，Fiedel和Geige ......但是我想要一直在搜索的单词不包含在结果中。我怎样才能做到这一点？

Answer 1

你想要w1.word是Violine的所有结果，除了w.word本身是Violine的那个？

SELECT w.word 
FROM words
AS w
INNER JOIN words as w1 ON w.meaning=w1.meaning
AND w1.word='Violine'
AND w.word <> 'Violine'

Answer 2

只需在WHERE子句中过滤它：

SELECT w.word 
FROM words
AS w
INNER JOIN words as w1 ON w.meaning=w1.meaning
AND w1.word  = 'Violine'
AND w.word <> w1.word