Question

我不确定我是否正在进行查询，但我只是PHP和postgresql的初学者，因此我的代码。

我想要完成的是使用日期选择器进行搜索，该日期选择器将提供日期数据：

<?php
$output = '';
if(isset($_POST['search'])) {
    $searchq = $_POST['search'];

    $query = ("SELECT trees.tree_type,tree_solds.transaction_id,tree_solds.actual_height,tree_solds.selling_height,tree_solds.sub_total,transactions.date_purchased FROM tree_solds
                                                    left join trees on tree_solds.tree_id = trees.id
                                                    left join transactions on transactions.id = tree_solds.transaction_id
                                                    WHERE date_purchased LIKE $searchq ");


                                        $result = pg_query($query); 
                                        if (!$result) { 
                                            echo "Problem with query " . $query . "<br/>"; 
                                            echo pg_last_error(); 
                                            exit(); 
                                        } 


                        $count = pg_num_rows($result);
                        if ($count == 0) {
                            $output = 'No Data on that date!';
                        } else {
                            while ($row = pg_fetch_array($result)) {
                               $output .= printf ("<tr><td>%s</td><td>%s</td><td>%s</td><td>%s</td><td>%s</td><td>%s</td></tr>", htmlspecialchars($myrow['transaction_id']), htmlspecialchars($myrow['date_purchased']), htmlspecialchars($myrow['tree_type']), htmlspecialchars($myrow['actual_height']), htmlspecialchars($myrow['selling_height']), number_format($myrow['sub_total'], 2));
                            }
                        }
                    }
                ?>

HTML表单

 <form action="location4.php" method="post">
 <input type="text" class="span2" name="search" value="" data-date-format="yyyy-mm-dd" id="dp2">

 <button type="submit" class="btn btn-default">Submit</button>
 </form>
 <?php print("$output");?>

继续收到此错误，但没有结果。

警告：pg_query（）：查询失败：ERROR：运算符不存在：没有时区的时间戳~~整数LINE 4：... WHERE date_purchased LIKE 2014 -... ^提示：没有运算符匹配给定的名称和参数类型。您可能需要添加显式类型转换。在第50行的/Applications/MAMP/htdocs/xmastool/location4.php问题查询SELECT trees.tree_type，tree_solds.transaction_id，tree_solds.actual_height，tree_solds.selling_height，tree_solds.sub_total，transactions.date_purchased FROM tree_solds left tree trees on tree_solds.tree_id = trees.id left 在transactions.id = tree_solds.transaction_id WHERE上加入事务 date_purchased LIKE 2014-12-07错误：运算符不存在：没有时区的时间戳~~整数LINE 4：... WHERE date_purchased LIKE 2014 -... ^提示：没有运算符匹配给定的名称和参数类型。您可能需要添加显式类型转换。

Answer 1

使用如下：WHERE date_purchased LIKE '%$searchq%'如果你只想要它的一部分。

如果您想要完全匹配，请WHERE date_purchased = '$searchq'

注意： %是LIKE中的小丑角色，请查看手册的使用方法。

Answer 2

试试这个

pg_query_params('SELECT ... WHERE DATE_TRUNC('day', date_purchased) = $1', array($searchq))

有关详细信息，请参阅[文档。您应始终确保正确转义查询参数（即，不会逐字连接到查询）以防止SQL注入。

Answer 3

由于polka_bolka的提示，

解决了这个问题。

 WHERE TO_CHAR(date_purchased, 'yyyy-mm-dd') LIKE '%$searchq%' ")

将date_purchased转换为char。

<?php
$output = '';
if(isset($_POST['search'])) {
    $searchq = $_POST['search'];

    $query = ("SELECT trees.tree_type,tree_solds.transaction_id,tree_solds.actual_height,tree_solds.selling_height,tree_solds.sub_total,transactions.date_purchased FROM tree_solds
                                                    left join trees on tree_solds.tree_id = trees.id
                                                    left join transactions on transactions.id = tree_solds.transaction_id
                                                    WHERE TO_CHAR(date_purchased, 'yyyy-mm-dd') LIKE '%$searchq%' ");


                                        $result = pg_query($query); 
                                        if (!$result) { 
                                            echo "Problem with query " . $query . "<br/>"; 
                                            echo pg_last_error(); 
                                            exit(); 
                                        } 


                        $count = pg_num_rows($result);
                        if ($count == 0) {
                            $output = 'No Data on that date!';
                        } else {
                            while ($row = pg_fetch_array($result)) {
                               $output .= printf ("<tr><td>%s</td><td>%s</td><td>%s</td><td>%s</td><td>%s</td><td>%s</td></tr>", htmlspecialchars($row['transaction_id']), htmlspecialchars($row['date_purchased']), htmlspecialchars($row['tree_type']), htmlspecialchars($row['actual_height']), htmlspecialchars($row['selling_height']), number_format($row['sub_total'], 2));
                            }
                        }
                    }
                ?>

Php postgresql搜索查询

3 个答案: