Question

有没有办法使用某些模式将文件的一部分读入数组作为“障碍”

# --------------------
[intermediate] --> STARTING POINT!
# intermediate dir (output dir of route chopper), is route files and
#   common files for each truck ready for customer format processing

PX12RUJ = /shares/MILKLINK/PPdir/lloydF/tempFiles/PX12RUJ/
PX12RUR = /shares/MILKLINK/PPdir/lloydF/tempFiles/PX12RUR/
PX12RUV = /shares/MILKLINK/PPdir/lloydF/tempFiles/PX12RUV/
#PX12RUU = /shares/MILKLINK/PPdir/lloydF/tempFiles/PX12RUU/
PX12WLJ = /shares/MILKLINK/PPdir/lloydF/tempFiles/PX12WLJ/
#PX12WLL = /shares/MILKLINK/PPdir/lloydF/tempFiles/PX12WLL/
PX12WLK = /shares/MILKLINK/PPdir/lloydF/tempFiles/PX12WLK/
PX12RUW = /shares/MILKLINK/PPdir/lloydF/tempFiles/PX12RUW/
WN14YGV = /shares/MILKLINK/PPdir/lloydF/tempFiles/WN14YGV/
WN14YGY = /shares/MILKLINK/PPdir/lloydF/tempFiles/WN14YGY/



# -------------------- 
[depotNum]-->END POINT

编辑：经过一番搜索和搞乱后，我已经管理了[intermediate]和[depotNum]之间的界限

但是在打印时会出现如下情况：

# intermediate dir (output dir of route chopper), is route files and

#   common files for each truck ready for customer format processing



PX12RUJ = /shares/MILKLINK/PPdir/lloydF/tempFiles/PX12RUJ/

PX12RUR = /shares/MILKLINK/PPdir/lloydF/tempFiles/PX12RUR/

PX12RUV = /shares/MILKLINK/PPdir/lloydF/tempFiles/PX12RUV/

#PX12RUU = /shares/MILKLINK/PPdir/lloydF/tempFiles/PX12RUU/

PX12WLJ = /shares/MILKLINK/PPdir/lloydF/tempFiles/PX12WLJ/

#PX12WLL = /shares/MILKLINK/PPdir/lloydF/tempFiles/PX12WLL/

PX12WLK = /shares/MILKLINK/PPdir/lloydF/tempFiles/PX12WLK/

PX12RUW = /shares/MILKLINK/PPdir/lloydF/tempFiles/PX12RUW/

WN14YGV = /shares/MILKLINK/PPdir/lloydF/tempFiles/WN14YGV/

WN14YGY = /shares/MILKLINK/PPdir/lloydF/tempFiles/WN14YGY/







# --------------------

这是我的代码，我试图去掉任何以＃或空白/空格开头的行，但出于某种原因，它不会削减额外的行

#!/usr/bin/python

FILE=open("/shares/MILKLINK/PPdir/lloydF/conDalt.ini" , 'r')
for LINE in FILE:
    LINE = filter(None,LINE)
    LINE = filter(lambda x: not x.startswith('#'), LINE)
    if LINE.strip() == '[intermediate]':
        break
for LINE in FILE:
    if LINE.strip() == '[depotNum]':
        break
    print LINE

Answer 1

import re
f=open("file.txt",'r')
print re.findall(r""+start_pattern+"[\s\S]+?"+end_pattern",f.read())

你可以试试这种东西

Answer 2

我会用：

import re
lines_list = []
with open(path,'r') as file:
    for line in file.readlines()
        if bool(re.match(you_regex, line)):
            lines_list.append(line)

读入行之间的数组

2 个答案: