Question

我刚刚开始使用JSLint来确保我创建的JavaScript代码至少符合某些标准，并且我收到了一个令人困惑的消息：

JSLint: Unexpected 'that'.

代码是实现进度条的解决方案的一部分，其中一部分是处理定时器和回调的对象，如下所示（这是从较大文件的开头提取的，我可以添加整个文件如果需要）：

var ProgressHandler = function () {
    "use strict";

    // Build a new object
    var that = {};

    // Add basic properties
    that.taskid = 0;
    that.timerid = 0; // Timer ID used to push refreshes
    that.progressUrl = ""; // URL to invoke to read progress
    that.interval = 500; // The interval for progress refresh
    that.taskProgressCallback = null; // The user-defined callback that refreshes the UI 
    that.taskCompletedCallback = null; // The user-defined callback that finalizes the call 

    // Set progress url
    that.setProgressUrl = function (url) {
        that.progressUrl = url;
        return this;
    }

    // Set frequency of refresh
    that.setInterval = function (interval) {
        that.interval = interval;
        return this;
    };

消息显示在以that.setInterval开头的行上。我还有其他用途，但JSLint也表示此时它会停止处理。我已尝试搜索此邮件，但此处未在此处或jslinterrors.com上列出。

为什么会出现这种情况，我该怎么做才能解决这个问题？或者它应该被忽略？

Answer 1

问题似乎是在;的定义之后没有that.setProgressUrl。改为：

    // Set progress url
    that.setProgressUrl = function (url) {
        that.progressUrl = url;
        return this;
    };

解决报告的问题。然后你有一个问题，你在文件的末尾缺少一个右括号和半冒号，不知道这只是一个复制和粘贴问题。完整的脚本应如下所示：

var ProgressHandler = function () {
    "use strict";

    // Build a new object
    var that = {};

    // Add basic properties
    that.taskid = 0;
    that.timerid = 0; // Timer ID used to push refreshes
    that.progressUrl = ""; // URL to invoke to read progress
    that.interval = 500; // The interval for progress refresh
    that.taskProgressCallback = null; // The user-defined callback that refreshes the UI 
    that.taskCompletedCallback = null; // The user-defined callback that finalizes the call 

    // Set progress url
    that.setProgressUrl = function (url) {
        that.progressUrl = url;
        return this;
    };

    // Set frequency of refresh
    that.setInterval = function (interval) {
        that.interval = interval;
        return this;
    };
};

JSLint意外地发现了这个＆＃39;信息

1 个答案: