Question

假设我的mongodb中有以下文档结构：

{
  _id: "tMSfNq9JR85XDaQe5"
  customerid: "QDGvBQhS6vYgZtnRr"
  employeeid: "QDGvBQhS6vYgZtnRr" 
  date: Sun Dec 07 2014 19:50:21 GMT+0800 (HKT) 
  projectid: "S83NEGHnrefvfASrf" 
  hours: 2
}

在查询特定日期范围内的数据时，是否有可能在特定项目和客户上花费总时间（按员工和日期分组），以便输出例如：

{ "projectid":"XXX", "date":"Dec 1, 2014", "employeeid":"AAA", "totalHrs":"20" }
{ "projectid":"XXX", "date":"Dec 1, 2014", "employeeid":"BBB", "totalHrs":"11" }
{ "projectid":"XXX", "date":"Dec 2, 2014", "employeeid":"AAA", "totalHrs":"3" }
{ "projectid":"XXX", "date":"Dec 2, 2014", "employeeid":"BBB", "totalHrs":"5" }
{ "projectid":"XXX", "date":"Dec 2, 2014", "employeeid":"CCC", "totalHrs":"18" }

由于

Answer 1

嗨，根据我的理解，我认为你想在projectid和employeeid上分组，看看你想要的输出，所以我认为下面的聚合可能适用于这种情况

db.collectionName.aggregate(
                       {"$group":{"_id":{"projectId":"$projectid","employeeId":"$employeeid","date":"$date"},
                       "totalHrs":{"$sum":"$hours"}}},
                      {"$project":{"projectid":"$_id.projectId",
                         "date":"$_id.date","employeeid":"$_id.employeeId",
                        "totalHrs":"$totalHrs",
                          "_id":0}}
                        )

Answer 2

您需要按照projectid，date，employeeid

进行分组

db.collectionname.aggregate({"$project":{"projectid":1,"date":1,"employeeid":1,"totalHrs":1}},
{"$group":{"_id":{"$projectId":"$projectid","date":"$date","employeeId":"$employeeid"}, 
"totalHrs":{"$sum":"$hours"}}})

日期范围内的Mongodb Sum字段和其他过滤器

2 个答案: