我试图将用户名和密码放入网页中的相应文本字段。首先我通过id找到电子邮件的元素并为其添加电子邮件,然后通过id找到密码的元素并为其输入密码,但在填写文本框中的电子邮件字段之前,它会跳转到密码字段并完成任务,我需要等待填写电子邮件,然后跳转到密码字段。
我尝试了隐式和明确的等待,但两者都不起作用请帮助我 我正在使用firefox和selenium 2.44
// Enter Email
driver.findElement(By.id("Email")).sendKeys("xxxxxxxx@gmail.com");
WebElement myDynamicElement = (new WebDriverWait(driver, 10)).until(ExpectedConditions.presenceOfElementLocated(By.id("Email")));
//driver.manage().timeouts().pageLoadTimeout(5, TimeUnit.SECONDS);
//Enter pwd
driver.findElement(By.id("Passwd")).sendKeys("xxxxx");
driver.manage().timeouts().implicitlyWait(5, TimeUnit.SECONDS);
// Click the sign in button
driver.findElement(By.id("signIn")).click();
编辑:这是我的完整代码
import java.util.concurrent.TimeUnit;
import org.openqa.selenium.By;
import org.openqa.selenium.WebDriver;
import org.openqa.selenium.WebElement;
import org.openqa.selenium.firefox.FirefoxDriver;
import org.openqa.selenium.support.ui.ExpectedConditions;
import org.openqa.selenium.support.ui.WebDriverWait;
public class Sample {
public static void main(String[] args) {
WebDriver driver = new FirefoxDriver();
driver.manage().timeouts().implicitlyWait(10, TimeUnit.SECONDS);
driver.get("https://www.google.com/");
driver.manage().timeouts().implicitlyWait(10, TimeUnit.SECONDS);
driver.manage().window().maximize();
driver.findElement(By.id("gbqfq")).sendKeys("gmail");
driver.manage().timeouts().implicitlyWait(10, TimeUnit.SECONDS);
driver.findElement(By.id("gbqfb")).click();
driver.findElement(By.xpath("//*[@id=\"rso\"]/div[2]/li[1]/div/h3/a[1]")).click();
// Click the sign in button
driver.findElement(By.id("gmail-sign-in")).click();
driver.manage().timeouts().pageLoadTimeout(10, TimeUnit.SECONDS);
// Enter Email
driver.findElement(By.id("Email")).sendKeys("xxx@gmail.com");
WebElement myDynamicElement = (new WebDriverWait(driver, 10)).until(ExpectedConditions.presenceOfElementLocated(By.id("Email")));
//Enter pwd
driver.findElement(By.id("Passwd")).sendKeys("@@@@xxx");
driver.manage().timeouts().implicitlyWait(10, TimeUnit.SECONDS);
// Click the sign in button
driver.findElement(By.id("signIn")).click();
}
}
答案 0 :(得分:0)
做一件事,首先进入电子邮件字段,然后在电子邮件字段上获取文本,它将为您提供输入的内容,如果是,则转到密码文本框。
答案 1 :(得分:0)
虽然我在我最后尝试时代码运行正常,仍然修改了现有代码。请查看这是否适合您:
WebDriver driver = new FirefoxDriver();
driver.manage().timeouts().implicitlyWait(20, TimeUnit.SECONDS);
driver.get("https://www.google.com/");
driver.manage().window().maximize();
driver.findElement(By.id("gbqfq")).sendKeys("gmail");
driver.findElement(By.id("gbqfb")).click();
driver.findElement(By.xpath("//a[.='Gmail - Google']")).click(); //Modified with a relative xpath
/*This part of clicking on Sign In Button wasn't coming up for me,
So, I've commented it. Please Uncomment, if this page is coming up for you*/
// Click the sign in button
// driver.findElement(By.id("gmail-sign-in")).click();
//driver.manage().timeouts().pageLoadTimeout(10, TimeUnit.SECONDS);
// Enter Email
driver.findElement(By.id("Email")).sendKeys("testing@gmail.com");
//Enter pwd
driver.findElement(By.id("Passwd")).sendKeys("tesing&*78");
// Click the sign in button
driver.findElement(By.id("signIn")).click();
答案 2 :(得分:0)
我有类似的情况。我的应用程序有一个回发脚本,导致文本框跳转到另一个位置。我的工作是先.click()首先回到webelement然后再做一个.sendkey()。希望这对你也有帮助。