Question

我试图通过加入介绍公司来搜索用户，并使用以下代码计算总充值交易

$data = Yii::app()->db->createCommand()->select('a.Id, a.UserName, a.Name, a.Sex, a.DOB, a.Email, a.ContactNo, a.Credit, a.EmailVerified, a.Level, a.CreatedTime, a.Active, a.Referral, a.ReceivedFirstTimeDepositBonus, b.Name AS ReferralName, COUNT(c.Id) AS TransactionCount')->from('user a')->leftJoin('company b', 'a.Referral=b.Id')->leftjoin('transaction c', 'a.Id = c.UserId')->group('a.Id');

$data = $data->andWhere('a.Role = 0');
$data = $data->andWhere('c.TransactionCount > 0');
$data = $data->queryAll();

但是yii给我这样的错误

找不到列：1054未知列＆c; .TransactionCount＆＃39;在＆＃39;哪里条款＆＃39 ;.执行的SQL语句是：SELECT a.Id，a.UserName， a.Name，a.Sex，a.DOB，a.Email，a.ContactNo，a.Credit，a.EmailVerified， a.Level，a.CreatedTime，a.Active，a.Referral， a.ReceivedFirstTimeDepositBonus，b.Name AS ReferralName，COUNT（c.Id） AS TransactionCount FROM user a LEFT JOIN company b ON a.Referral = b.Id LEFT JOIN transaction c ON a.Id = c.UserId WHERE （a.Role = 0）AND（c.TransactionCount＆gt; 0）GROUP BY a。Id ORDER BY Id限制20

我试着长时间查看查询，但我不知道问题是什么我不知道为什么它会让我犯错误，即使我尝试

$data = $data->andWhere('TransactionCount > 0');

但是只有列名不同才能得到相同的错误

Answer 1

您不能在WHERE子句中使用别名。

更换

$data = $data->andWhere('c.TransactionCount > 0');

与

$data = $data->having('COUNT(c.Id) > 0');

或

$data = $data->having('TransactionCount > 0');

应该这样做。

Answer 2

您的TransactionCount不是真正的列，而是查询执行后的产品。这就是SQL无法找到它的原因。

将c.TransactionCount > 0替换为COUNT(c.Id) > 0
或者更好地使用HAVING TransactionCount > 0。 In Yii having看起来像->having('TransactionCount > :desiredCount', [':desiredCount' => 0])

Answer 3

cluase始终在group_by --aggregate函数

之前执行

SELECT a.Id，a.UserName，a.Name，a.Sex，a.DOB，a.Email，a.ContactNo，a.Credit，a.EmailVerified，a.Level，a.CreatedTime，a。 Active，a.Referral，a.ReceivedFirstTimeDepositBonus，b.Name AS ReferralName，COUNT（c.Id）AS TransactionCount FROM user LEFT JOIN company b ON a.Referral = b.Id LEFT JOIN transaction c ON a.Id = c。 UserId WHERE（a.Role = 0）AND（count（c.Id）＆gt; 0）GROUP BY a.Id ORDER BY Id LIMIT 20

在COUNT LEFT JOIN上找不到列

3 个答案: