Question

我正在尝试编写一个需要用户输入的小游戏。

while True:
    x = raw_input("\n> ")

    if x in ["Susan", "Foreman"] and not grand_name: 
        print "The button glows! You have guessed the password! You can press the button now"
        grand_name = True
    elif x in ["Press", "press", "button"] and not grand_name:
        print "You have to guess the password first!"
    elif x in ["Press", "press", "button"] and grand_name:
        print "The TARDIS materializes around the Doctor! He has been freed from a gaseous monster!"
        end()
    else:
        print "Try Again."

我想这样做，以便用户可以输入“按下按钮”或“我按下按钮”来满足所需的elif语句，而不是他们必须完全键入列表的对象。如果单词本身在输入中的任何位置，我只希望语句运行。有没有一种方法可以让Python识别输入是否包含列表中的单词而不是完全键入单词？我希望这是有道理的。这是我提出的第一个问题，所以我还在学习。感谢。

我尝试使用下面示例中的any（），但它返回错误“未定义全局名称w”

虽然是真的： x = raw_input（“\ n＆gt;”） opt1 = [“苏珊”，“工头”] opt2 = [“按”，“按”，“按钮”]

    if any(z in x for z in opt1): 
        print "The button glows! You have guessed the password! You can press the button now"
        grand_name = True
    elif any(w in x for w in opt2) and not grand_name:
        print "You have to guess the password first!"
    elif any(w in x for x in opt2) and grand_name:
        print "The TARDIS materializes around the Doctor! He has been freed from a gaseous monster!"
        end()
    else:
        print "Try Again."

Answer 1

你的意思是if "press" in x.lower() or "button" in x.lower()？

>>> "press" in "some sentence with the word press in it"
True

>>> words = ["press","button","otherword"]
>>> any(w in "aaa press bbb" for w in words)
True
>>> any(w in "aaa button bbb" for w in words)
True
>>> any(w in "aaa bbb" for w in words)
False

raw_input（）with＆＃34; if .... in ..＆＃34;声明

1 个答案: