我在mongo db中编写查询。我有一张预订表,我希望在一个月内获得预订数量,即按月分组。我很困惑如何从约会中获得月份。
这是我的架构:
{
"_id" : ObjectId("5485dd6af4708669af35ffe6"),
"bookingid" : 1,
"operatorid" : 1,
"clientid" : null,
"callername" : "Sayem Hussain",
"contactno" : "0205661862",
"regular" : 0,
"bookingdetail" : [
{
"driverid" : 1,
"pickupdatetime" : "2011-04-14 11:00:00",
"from" : "white chapel",
"to" : "beach",
"cost" : 500,
"journeytime" : 60
},
{
"driverid" : 2,
"pickupdatetime" : "2012-05-14 12:00:00",
"from" : "walthamstow",
"to" : "mile end",
"cost" : 1000,
"journeytime" : 50
}
],
"bookingdatetime" : "2012-10-11T07:00:00Z"
}
{
"_id" : ObjectId("5485dd6af4708669af35ffe7"),
"bookingid" : 2,
"operatorid" : 1,
"clientid" : 1,
"callername" : null,
"contactno" : "0205561281",
"regular" : 1,
"bookingdetail" : [
{
"driverid" : 3,
"pickupdatetime" : "2012-02-12 09:00:00",
"from" : "grange park",
"to" : "queen mary",
"cost" : 650,
"journeytime" : 90
},
{
"driverid" : 2,
"pickupdatetime" : "2012-02-13 06:00:00",
"from" : "drapers bar",
"to" : "naveed restaurant",
"cost" : 1350,
"journeytime" : 120
}
],
"bookingdatetime" : "2014-07-26T05:00:00Z"
}
{
"_id" : ObjectId("5485dd6af4708669af35ffe8"),
"bookingid" : 3,
"operatorid" : 2,
"clientid" : 2,
"callername" : null,
"contactno" : "02565138632",
"regular" : 1,
"bookingdetail" : [
{
"driverid" : 2,
"pickupdatetime" : "2013-11-23 06:00:00",
"from" : "hussainabad",
"to" : "lyari",
"cost" : 2450,
"journeytime" : 240
},
{
"driverid" : 1,
"pickupdatetime" : "2013-11-25 08:00:00",
"from" : "garden",
"to" : "defence",
"cost" : 1800,
"journeytime" : 30
}
],
"bookingdatetime" : "2014-03-17T11:00:00Z"
}
这是我尝试过的:
db.booking.aggregate([{$group:{_id:new Date("$bookingdatetime").getMonth(), numberofbookings:{$sum:1}}}])
然后它返回:
{ "_id" : NaN, "numberofbookings" : 3 }
我哪里错了?请帮助我。
答案 0 :(得分:12)
您需要在群组中使用$ month关键字。您的new Date().getMonth()
来电只会发生一次,并会尝试创建一个月的字符串" $ bookingdatetime"。
db.booking.aggregate([
{$group: {
_id: {$month: "$bookingdatetime"},
numberofbookings: {$sum: 1}
}}
]);
答案 1 :(得分:9)
您不能在汇总管道中包含任意JavaScript,因为您将bookingdatetime
存储为string
而不是Date
,因此无法使用{{1运营商。
但是,因为您的日期字符串遵循严格的格式,您可以使用$substr
运算符从字符串中提取月份值:
$month
输出:
db.test.aggregate([
{$group: {
_id: {$substr: ['$bookingdatetime', 5, 2]},
numberofbookings: {$sum: 1}
}}
])
答案 2 :(得分:0)
您可以使用 $toDate
运算符将字符串转换为日期。在某种程度上,我添加到 answer 给出的 Will Shaver。通过采用这种方法,我能够实现您想要的。
db.booking.aggregate([
{
$project: {
month: { $month: { $toDate: "$bookingdatetime" } },
}
},
{
$group: {
_id: { month: "$month" },
numberofbookings: { $sum: 1 }
}
}
]);