Question

有一个日期时间字段，并且想要计算日差。在下一步中，我希望为不同的时间间隔设置不同的列，使用0或1。

基表的结构是名称和日期。

输出应如下所示：

name|date                   |days|interval 0-31 |interval 31-60|
Tim |2014-12-07 08:04:25.000|1   |1             |0             |
Tom |2014-10-28 08:04:25.000|42  |0             |1             |

提前帮助你！

Answer 1

如果您想要计算落入指定间隔的记录，那么这样的事情就可以了。只需重复SUM（Case ...行，每个时间间隔修改范围检查。

SELECT        
   SUM(CASE WHEN DayCount > 0 AND DayCount < 31 THEN 1 ELSE 0 END) AS ZeroTo31
FROM            
  (SELECT        
       DATEDIFF(dy, StartDate, EndDate) AS DayCount
    FROM YourTable) AS sub

Answer 2

那么：

SELECT        StartDate, DayCount, CASE WHEN DayCount > 0 AND DayCount < 31 THEN 1 ELSE 0 END AS  daysZeroTo31,
  CASE WHEN DayCount > 31 AND DayCount < 60 THEN 1 ELSE 0 END AS days31to60
FROM            (SELECT        StartDate, EndDate, DATEDIFF(dy, StartDate, EndDate) AS DayCount
  FROM            YourTable) AS sub

计算日期并以不同的间隔显示结果

2 个答案: