Question

请帮助我不知道这是我的模型有什么不对

    public function searchstudents(){
    $establishment_name = $this->input->post('name');
    $address = $this->input->post('address');
    $establishment_name2 = "Nicole's Apartment";


        $query = $this->db->query("SELECT u.id as id, u.first_name as firstname, u.middle_name as                  middlename, u.last_name as lastname, e.name as establishmentname FROM users u, beds b, room r, establishment e WHERE  r.establishment_id = e.id AND u.id = b.student_id  AND b.room_id = r.room_id AND e.name = '$establishment_name2' ");

  $this->db->query($query);

    return $query->result_array(); 

}

当我删除AND e.name ='$ establishment_name2'时它可以工作但是当我包含它时，它会导致调用非对象上的成员函数result_array（）。我在mysql中尝试了查询并且它可以工作，但它在codeigniter中不起作用。

Answer 1

您需要转义$establishment_name2：

$query = $this->db->query("SELECT u.id as id, u.first_name as firstname, u.middle_name as                  middlename, u.last_name as lastname, e.name as establishmentname FROM users u, beds b, room r, establishment e WHERE  r.establishment_id = e.id AND u.id = b.student_id  AND b.room_id = r.room_id AND e.name = ".$this->db->escape($establishment_name2));

Answer 2

这是一个问题：

$establishment_name2 = "Nicole's Apartment";

变为：

e.name = 'Nicole's Apartment'

查询中的

使用addslashes（）或像Mudshark说的那样逃避

Answer 3

Noooo，看你可以直接这样做

$this->db->query('SELECT u.id as id, u.first_name as firstname, u.middle_name as                  middlename, u.last_name as lastname, e.name as establishmentname FROM users u, beds b, room r, establishment e WHERE  r.establishment_id = e.id AND u.id = b.student_id  AND b.room_id = r.room_id AND e.name = ?', array($establishment_name2));

$ this-＆gt; db-＆gt; query（）接受3个参数：

1 - Query
2 - Array (with parameters, all parameters are clean)
3 - Escape string.

在非对象上调用成员函数result_array（）

3 个答案: