Question

我想了解如何在Questions方法中使用排序算法（代码的最后一种方法），以便按顺序对每个玩家的名称进行排序。我不能将它放在Main方法中，因为它需要来自Question Method中循环的（名称）字符串。

    public static void main(String[] args){
    int players = Integer.parseInt(JOptionPane.showInputDialog("Please tell me how many players are taking part in this quiz!"));


            /* --------------------------- Questions in Arrays --------------------------- */ 

        String[] question = {"Question 1: ",
                         "Question 2: ",
                         "Question 3: ",
                         "Question 4: ",
                         "Question 5: " };

            String[] answer = {"ans1",
                               "ans2",
                               "ans3",
                               "ans4",
                               "ans5" };




questions(question, answer, players);

            /* --------------------------- Questions in Arrays --------------------------- */ 
}                       /* End of Main Method */




            /* Questions Method */

public static void questions(String[] question, String[] answer, int n) {

        String[] name = new String[n];  // Player Names 
        int[] playerscore = new int[n]; // Argument for Score
        String[] que = new String[question.length]; //Questions for Loops



            /* --------------------------- For loop for number of players --------------------------- */ 
    for (int i = 0; i < n; i++)
    {
        playerscore[i] = 0;
        name[i] = JOptionPane.showInputDialog("What is your name player"+ (i+1) +"?");
        JOptionPane.showMessageDialog(null,"Hello :"+ name[i] + " Player number " +(i+1)+ ". I hope your ready to start!");


            /* --------------------------- Loop in Loop for questions --------------------------- */ 
        for (int x=0; x<question.length; x++) {
            que[x] = JOptionPane.showInputDialog(question[x]);
                if(que[x].equals(answer[x]))
                    {

                        playerscore[i] = playerscore[i] + 1;

                    }

        else {
                JOptionPane.showMessageDialog(null,"Wrong!");
             }

                } // End for loop for Question



        System.out.println("\nPlayer: "+(i+1)+ " Name: "+name[i]+"\tScore"+playerscore[i]+" out of 5.);





            /* --------------------------- Loop in Loop for questions --------------------------- */ 



           } // End for loop for player number

              } //End method questions

public static void sortNames（String name []）{

int i;
boolean flag = true;  // will determine when the sort is finished
String temp;

  while(flag) { // while flag is true
    flag = false;
        for (i = 0; i < name.length-1; i++) {
          if (name[i].compareToIgnoreCase(name[i+1]) > 0 ) {
            temp = name[i];
            name[i] = name[i+1];     // swapping
            name[i+1] = temp;
            flag = true;
                }
            }
    }

}

       /* --------------------------- Score Display --------------------------- */

}

Answer 1

让你的问题方法返回带有玩家名字的数组这样您就可以使用返回的值来调用sortNames方法。

Answer 2

为什么不使用Arrays.sort（）方法对名称进行排序？您正在使用复杂的方法对字符串进行排序。

public static String[] sortNames(String name[]) 
{
    Arrays.sort(name);
    return name;
}

供参考Sort Array in Java

如果你想轻松，那么你可以为每个玩家创建一个对象并将其保存在HashMap中。

你可以在java中使用HashMap，使用key作为你的玩家名称 - String和Value作为一个对象，包含你需要拥有的玩家的所有信息。

Map<String, Object> map = new HashMap<String, Object>();

您也可以像

那样对该hashmap进行排序

HashMap<String, PlayerInfo> map = new HashMap<String, PlayerInfo>();
ValueComparator bvc =  new ValueComparator(map);
TreeMap<String,PlayerInfo> sorted_map = new TreeMap<String,PlayerInfo>(bvc);

map.put(playerName1, playerInfo1);
map.put(playerName2, playerInfo2);

map.put(playerNamen, playerInfon);

sorted_map.putAll(map);

System.out.println("results: "+sorted_map);

排序算法[实现方法]

2 个答案: