我在php中创建了我的第一个关联多维数组，我想知道一个关键 - 是否使用它。我正在创建一个用户输入食物名称的表单。当他们提交表单时，php处理程序将搜索我的多维数组，查看是否匹配，如果是，则显示与该食物相关的数据。
以表格形式，这很简单：
NAME / VALUE / ADD＆＃39; L INFO / NUTRITIONAL INFO 苹果/是/适合你/卡路里：57 份量：1杯（等 - 这里有很多值）
所以我认为我有两个选择：
//first possible choice
$yesorno = array(
array( Name => "apples",
Value => "yes",
Addinfo => 15
nutrinfo => array (
"Serving Size" => "1 cup sliced",
"Calories" => 57,
"Carbohydrates" => "15 g",
"Total Fat" => "0.2 g",
"Saturated Fat" => "0 g",
"Fiber" => "2.6 g",
"Protein" => "0.3 g" ,
"Vitamin A" => "59 IU",
"Vitamin C" => "5 mg",
"Vitamin B6" => 0,
"Vitamin B12" => 0,
"Vitamin D" => 0,
"Calcium" => "7 mg",
"Magnesium" => "5 mg",
"Iron" => "0.1 mg",
"Potassium" => "0.1 mg",
"Sodium" => "1 mg"
),
),
array( Name => "bananas",
Value => "yes",
Addinfo => 25,
),
array( Name => "cauliflower",
Value => "yes",
Addinfo => 7
)
);
或者这个：
$yesorno = array (
"apples" => array (
"name" => "apples",
"value" => "Yes",
"addinfo" => "",
"nutrinfo" => array (
"Serving Size" => "1 cup sliced",
"Calories" => 57,
"Carbohydrates" => "15 g",
"Total Fat" => "0.2 g",
"Saturated Fat" => "0 g",
"Fiber" => "2.6 g",
"Protein" => "0.3 g" ,
"Vitamin A" => "59 IU",
"Vitamin C" => "5 mg",
"Vitamin B6" => 0,
"Vitamin B12" => 0,
"Vitamin D" => 0,
"Calcium" => "7 mg",
"Magnesium" => "5 mg",
"Iron" => "0.1 mg",
"Potassium" => "0.1 mg",
"Sodium" => "1 mg"
),
),
"bananas" => array (
"name" => "bananas",
"value" => "yes",
"addinfo" => "",
"nutrinfo" => array (
"Serving Size" => "1 cup sliced",
"Calories" => 57,
"Carbohydrates" => "15 g",
"Total Fat" => "0.2 g",
"Saturated Fat" => "0 g",
"Fiber" => "2.6 g",
"Protein" => "0.3 g" ,
"Vitamin A" => "59 IU",
"Vitamin C" => "5 mg",
"Vitamin B6" => 0,
"Vitamin B12" => 0,
"Vitamin D" => 0,
"Calcium" => "7 mg",
"Magnesium" => "5 mg",
"Iron" => "0.1 mg",
"Potassium" => "0.1 mg",
"Sodium" => "1 mg"
),
),
);
所以我想知道选项1和选项2之间的区别 - 区别在于选项2有第二个数组的键，而第一个数组没有。我将搜索名称，然后检索名称，值，附加信息和营养信息（包含许多值）。
使用选项2中的密钥或不使用选项1中的密钥更好吗？让＃34;苹果＆＃34; /＆＃34;香蕉＆＃34;等两次似乎是多余的。如果我使用密钥，当我通过阵列搜索＆＃34; apples＆＃34;时会出现问题。或者该人在表格上输入的任何食物名称，因为同一名称被列出两次？
另外，你真的需要在密钥周围加上引号（例如，＆＃34;名称＆＃34;）还是可选的？
答案 0 :(得分：2)
我建议使用后面的数组声明形式，因为没有混淆或冲突来选择具有该关联键的元素，如果你想在这个例子中创建使用key来识别苹果的任何数组，你可以创建一个数组如下，所以它会解决你的冲突。
$yesorno = array ( 'apples'=>array(
'applename'=>array(
"value" => "Yes",
"addinfo" => "",
"nutrinfo" => array (
"Serving Size" => "1 cup sliced",
"Calories" => 57,
"Carbohydrates" => "15 g",
"Total Fat" => "0.2 g",
"Saturated Fat" => "0 g",
"Fiber" => "2.6 g",
"Protein" => "0.3 g" ,
"Vitamin A" => "59 IU",
"Vitamin C" => "5 mg",
"Vitamin B6" => 0,
"Vitamin B12" => 0,
"Vitamin D" => 0,
"Calcium" => "7 mg",
"Magnesium" => "5 mg",
"Iron" => "0.1 mg",
"Potassium" => "0.1 mg",
"Sodium" => "1 mg"
),
),
'applename2'=>array(
"value" => "Yes",
"addinfo" => "",
"nutrinfo" => array (
"Serving Size" => "1 cup sliced",
"Calories" => 57,
"Carbohydrates" => "15 g",
"Total Fat" => "0.2 g",
"Saturated Fat" => "0 g",
"Fiber" => "2.6 g",
"Protein" => "0.3 g" ,
"Vitamin A" => "59 IU",
"Vitamin C" => "5 mg",
"Vitamin B6" => 0,
"Vitamin B12" => 0,
"Vitamin D" => 0,
"Calcium" => "7 mg",
"Magnesium" => "5 mg",
"Iron" => "0.1 mg",
"Potassium" => "0.1 mg",
"Sodium" => "1 mg"
),
),
)
);
如果我理解你的问题，那么我希望这会给你解决方案。并且密钥的引号是必要的，因为如果你分配一个值，解析器会将它视为变量并产生错误，变量是找不到错误。谢谢。