Question

代码中的

字符串查询无法识别，因此plZ告诉我删除错误的确切答案因为如果它是错误我不能得到该精确产量在代码中，字符串查询无法识别，因此plZ告诉我删除错误的确切答案因为如果它是错误我不能得到该精确输出

package sample.com;

import java.io.IOException;
import javax.servlet.ServletException;
import javax.servlet.annotation.WebServlet;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
import java.io.BufferedReader;
import java.io.InputStreamReader;
import java.net.URL;
import java.net.URLConnection;
import java.net.URLEncoder;
import org.json.JSONArray;      // JSON library from http://www.json.org/java/
import org.json.JSONObject;
/**
 * Servlet implementation class GoogleMap
 */
@WebServlet("/GoogleMap")
public class GoogleMap extends HttpServlet {
    private static final long serialVersionUID = 1L;
    private final String HTTP_REFERER = "http://www.shikshasolutions.net/";
    public void GoogleQuery() {
        makeQuery("viral");
        makeQuery("info:http://google.com/");
        makeQuery("site:google.com");
        }



    private void makeQuery(String query) {

        System.out.println("\nQuerying for " + query);
    }



    /**
     * @see HttpServlet#HttpServlet()
     */
    public GoogleMap() {
        super();
        // TODO Auto-generated constructor stub
    }

    /**
     * @see HttpServlet#doGet(HttpServletRequest request, HttpServletResponse response)
     */
    protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {




try
{
// Convert spaces to +, etc. to make a valid URL
 String query = URLEncoder.encode(query, "UTF-8");

URL url = new URL("http://ajax.googleapis.com/ajax/services/search/web?start=0&rsz=large&v=1.0&q=" + query);
URLConnection connection = url.openConnection();
connection.addRequestProperty("Referer", HTTP_REFERER);

// Get the JSON response
String line;
StringBuilder builder = new StringBuilder();
BufferedReader reader = new BufferedReader(
new InputStreamReader(connection.getInputStream()));
while((line = reader.readLine()) != null) {
builder.append(line);
}

String response1 = builder.toString();
JSONObject json = new JSONObject(response1);

System.out.println("Total results = " + json.getJSONObject("responseData").getJSONObject("cursor").getString("estimatedResultCount"));
JSONArray ja = json.getJSONObject("responseData")
.getJSONArray("results");

System.out.println("\nResults:");
for (int i = 0; i < ja.length(); i++) {
System.out.print(("ss"+i+1) + ". ");
JSONObject j = ja.getJSONObject(i);
System.out.println(j.getString("titleNoFormatting"));
System.out.println(j.getString("url"));
}
}
catch (Exception e) {
System.err.println("Something went wrong...");
e.printStackTrace();
}
}


    }

    /**
     * @see HttpServlet#doPost(HttpServletRequest request, HttpServletResponse response)
     */

Answer 1

在你的行中：

String query = URLEncoder.encode(query, "UTF-8");

您正在尝试使用未实例化的查询值来实例化查询的值。是否应该用以下内容代替：

String query = URLEncoder.encode(request.getQueryString(), "UTF-8");

我不完全确定你在这里做什么或者你真正的问题是什么，但这是我要开始的地方。

我如何获得以下代码的输出

1 个答案: