Question

我有一个以下数组，显示用户的信息和与用户相关的一些值。以下数组包含两个用户Akiyo Riggs和Bingo的信息

a1 = [["Akiyo Riggs", -32, "OverTime Hours", "",12],["Akiyo Riggs", -32, 
"Regular Hours", "", 18],["Bingo",-12,"OverTime Hours","",14], ["Bingo",
-12,"Regular Hours","",32]]

如何转换为以下哈希数组，其中键是用户名，值是具有相应值的哈希

[{"Akiyo Riggs"=>{"OverTime Hours"=>["", 12], "Regular Hours"=>["", 18]},
{"Bingo"=>{"OverTime Hours"=>["", 14], "Regular Hours"=>["", 32]}]

Answer 1

a1.map { |x,_,p,*ps| {x => {p => ps} } }.reduce({}, :deep_merge)
# => {"Akiyo Riggs"=>{"OverTime Hours"=>["", 12], "Regular Hours"=>["", 18]},
#     "Bingo"=>{"OverTime Hours"=>["", 14], "Regular Hours"=>["", 32]}}

注意：如果要考虑效率，请考虑使用deep_merge!而不是deep_merge，以便reduce在每次迭代时都不会创建新的哈希。

一些解释：

a1.map { |x,_,p,*ps| {x => {p => ps} } }

为我们提供了一系列像这样的哈希

 [{"Akiyo Riggs"=>{"OverTime Hours"=>["", 12]}},
  {"Akiyo Riggs"=>{"Regular Hours"=>["", 18]}},
  {"Bingo"=>{"OverTime Hours"=>["", 14]}},
  {"Bingo"=>{"Regular Hours"=>["", 32]}}]

我们可以递归地与ActiveSupport Hash#deep_merge

合并

Answer 2

你可以做这样的事情（然而，这并不完全是你想要的）：

res = a1.group_by {|x| x[0] }.reduce({}) {|h, x| h[ x[0] ] = x[1].reduce({}) {|hh, xx| hh[ xx[2] ] = xx[3..-1] ; hh } ; h }
# => {"Akiyo Riggs"=>{"OverTime Hours"=>["", 12], "Regular Hours"=>["", 18]}, "Bingo"=>{"OverTime Hours"=>["", 14], "Regular Hours"=>["", 32]}}

确切的事情是采取额外步骤：

res.keys.map {|k| {k => res[k]}}
# => [{"Akiyo Riggs"=>{"OverTime Hours"=>["", 12], "Regular Hours"=>["", 18]}}, {"Bingo"=>{"OverTime Hours"=>["", 14], "Regular Hours"=>["", 32]}}]

Answer 3

a1.each_with_object({}) do |array, result|
  result[array[0]] ||= {}
  result[array[0]].merge!(array[2] => [array[3], array[4]])
end.map { |k, v| { k => v } }

# => [{"Akiyo Riggs"=>{"OverTime Hours"=>["", 12], "Regular Hours"=>["", 18]}}, {"Bingo"=>{"OverTime Hours"=>["", 14], "Regular Hours"=>["", 32]}}]

Answer 4

array.each_with_object({}) do |(name, _, hours_type, a, b), hash|
  hash[name] ||= {}
  hash[name][hours_type] = [a, b]
end.map do |name, values_hash|
  {name => values_hash}
end

使用以下结构将Array转换为带有ruby的Hash

4 个答案: