Question

我有一个问题，我无法找到答案。

如何仅在current_version为1的情况下预先形成搜索查询？我已经尝试了下面的查询但是没有用。

SELECT labtest_id AS id, 
       labtest_name AS name, 
       labtest_request_code, 
       labtest_synonym, 
       labtest_current_version, 
       labtest_version 
FROM labtests 
WHERE labtest_current_version = 1 AND labtest_name LIKE %imap% OR labtest_request_code 
LIKE %imap% OR labtest_synonym LIKE %imap%

searchkey = test5

-------------------------------------------------------------------
| id | name  | request_code | synonym | current_version | version |
-------------------------------------------------------------------
| 1  | test1 | 74532        | one     | 1               | 1.00    |
| 2  | test2 | 74432        | two     | 1               | 0.00    |
| 3  | test3 | 78962        | three   | 0               | 2.05    |
| 4  | test4 | 72111        | four    | 0               | 1.07    |
| 5  | test5 | 90322        | five    | 1               | 2.00    |
-------------------------------------------------------------------

因此，在此示例中，搜索查询需要显示第1行

-------------------------------------------------------------------
| id | name  | request_code | synonym | current_version | version |
-------------------------------------------------------------------
| 5  | test5 | 90322        | five    | 1               | 2.00    |
-------------------------------------------------------------------

Answer 1

你只是在你的OR条款和引号周围错过了括号：

SELECT labtest_id AS id, 
    labtest_name AS name, 
    labtest_request_code, 
    labtest_synonym, 
    labtest_current_version, 
    labtest_version
FROM labtests
WHERE labtest_current_version = 1
  AND (labtest_name LIKE '%imap%'
      OR labtest_request_code LIKE '%imap%'
      OR labtest_synonym LIKE '%imap%')

如果省略括号，则最后两个OR子句将返回行labtest_current_version值，due to operator precedence和布尔定律。

Answer 2

您需要将OR条件分组为：

WHERE labtest_current_version = 1 AND (labtest_name LIKE %imap% OR labtest_request_code LIKE %imap% OR labtest_synonym LIKE %imap%)

Answer 3

需要通过将OR部分与()

分组来分离AND / OR运算符

SELECT labtest_id AS id, 
    labtest_name AS name, 
    labtest_request_code, 
    labtest_synonym, 
    labtest_current_version, 
    labtest_version
FROM labtests
WHERE labtest_current_version = 1 AND (labtest_name LIKE %imap% OR labtest_request_code LIKE %imap% OR labtest_synonym LIKE %imap%)

PHP MYSQL查询，只搜索字段为true的行

3 个答案: