无法以编程方式下载.eps文件

时间:2014-12-08 09:43:59

标签: c# asp.net download eps

我创建了一个代码,用户可以从中下载该文件。将下载的文件仅用于图像文件。

我的代码如下所示。

try
{
    System.IO.FileInfo fileInfo = new FileInfo(file.Name);
    // replace special characters with blank.
    string filename = GeneralMethods.MakeValidFileName(Path.GetFileNameWithoutExtension(file.Name));
    filename += fileInfo.Extension;
    byte[] obj = (byte[])file.OpenBinary();
    Response.Clear();
    Response.ClearContent();
    Response.ClearHeaders();
    Response.Cache.SetCacheability(System.Web.HttpCacheability.Private);
    Response.AppendHeader("Content-Disposition", "attachment; filename= " + filename);
    Response.ContentType = MimeMapping.GetMimeMapping(filename);
    if (Response.IsClientConnected)
        Response.BinaryWrite(obj);
    Response.Flush();
   // Response.Close();
    HttpContext.Current.ApplicationInstance.CompleteRequest();

}
catch (Exception ex)
{       
}
finally
{

}

当我使用此代码下载.eps文件时,无法在客户端应用程序中打开该文件。

我的代码中缺少什么?

2 个答案:

答案 0 :(得分:0)

尝试修改此行:

Response.AppendHeader("Content-Disposition", "attachment; filename= " + filename);

看起来像这样:

var cd = new System.Net.Mime.ContentDisposition
{
    FileName = filename,
    Inline = false,
};

Response.AddHeader("Content-Disposition", cd.ToString());

过去,像这样添加Content-Disposition对我有用。

答案 1 :(得分:0)

尝试各种代码后,终于找到了答案。

我的代码中唯一缺少的是在Response对象中定义“Content-Length”标头。

所以代码如下:

try
{
    System.IO.FileInfo fileInfo = new FileInfo(file.Name);
    string filename = GeneralMethods.MakeValidFileName(Path.GetFileNameWithoutExtension(file.Name));
    filename += fileInfo.Extension;
    byte[] obj = (byte[])file.OpenBinary();
    Response.Clear();
    Response.ClearContent();
    Response.ClearHeaders();
    Response.Cache.SetCacheability(System.Web.HttpCacheability.Server);
    var cd = new System.Net.Mime.ContentDisposition { FileName = file.Name, Inline=false};
    Response.AppendHeader("Content-Disposition", cd.ToString());
    Response.AppendHeader("Content-Length",obj.Length.ToString());
    Response.ContentType = MimeMapping.GetMimeMapping(filename);                
    if (Response.IsClientConnected)
        Response.BinaryWrite(obj);
    Response.Flush();
   // Response.Close();
    HttpContext.Current.ApplicationInstance.CompleteRequest();
}
catch (Exception ex)
{       
    Response.Redirect(Request.UrlReferrer.ToString());
}
finally
{
}

现在它在我的情况下工作...... !!! : - 。)

希望这对其他人也有帮助..

由于