我想在字符串中获取客户端的到达日期并将其作为参数传递给strToCal方法,此方法返回具有该日期的Calendar对象,但它不起作用,id得到解析异常错误:
static String pattern = "yyyy-MM-dd HH:mm:ss";
System.out.println("enter arrival date ("+ pattern +"):\n" );
c.setArrDate(strToCal(sc.next(),c));
System.out.println("enter departure date ("+ pattern +"):\n");
c.setResTilDate(strToCal(sc.next(),c));
static Calendar strToCal(String s, Client c) throws ParseException {
try{
DateFormat df = new SimpleDateFormat(pattern);
Calendar cal = Calendar.getInstance();
cal.setTime(df.parse(s));
return cal;
} catch(ParseException e){
System.out.println("somethings wrong");
return null;
}
答案 0 :(得分:2)
将sc.next()
替换为sc.nextLine();
因为sc.next()
将在第一个空格中拆分,而您的输入字符串不会是正确的模式。
修改我已尝试过此代码:
public class Test4 {
static String pattern = "yyyy-MM-dd HH:mm:ss";
public static void main(String[] args) {
Calendar c = Calendar.getInstance();
final Scanner input = new Scanner(System.in);
System.out.println("input date: ");
String a = input.nextLine();
c = strToCal(a);
System.out.println(c.getTime());
}
static Calendar strToCal(String s) {
try {
DateFormat df = new SimpleDateFormat(pattern);
Calendar cal = Calendar.getInstance();
cal.setTime(df.parse(s));
return cal;
} catch (ParseException e) {
e.printStackTrace();
return null;
}
}
}
next()
:
input date:
2014-05-16 13:30:00
java.text.ParseException: Unparseable date: "2014-05-16"
at java.text.DateFormat.parse(Unknown Source)
nextLine()
:
input date:
2014-05-16 13:30:00
Fri May 16 13:30:00 EEST 2014