Question

问题1： c＃ ProjectText 的默认解决方案文件的格式是否始终相同？

Project(Solution GUI) = SolutionName , ProjectPath, csProjPath, ProjectGUI

e.g：

Project("{FAE14EC0-321D-12D3-GF35-01C04F79EFBC}") = "WindowsFormsApplication26", "WindowsFormsApplication26\WindowsFormsApplication26.csproj", "{25F0453B-9C88-4C9E-AG6A-97873BB6EA23}"
EndProject

格式如下：1，它将具有解决方案GUI，然后是solutionName，然后是csproj 路径然后projectGUI

问题2： 我已经创建了一个正则表达式来获取.sln生成的文本，这就是我所拥有的：

Regex projectRegex = new Regex(@"Project\(\""([^\""]+)\""\)\s*\=\s*\""([^\""]+)\""\,\s*\""([^\""]+)""\,\s*\""([^\""]+)""");

但我不确定我的正则表达式中是否存在与第一个问题相关的错误，所以我想如果有更好的正则表达式或任何条件（例如解析或任何必须更快）才能获得ProjectText < / em>具体（我需要得到的）是csProj路径（在Group3上面的正则表达式模式上）

以及在Q1上显示的示例中应用的组：

Group1: {FAE14EC0-321D-12D3-GF35-01C04F79EFBC} Group2: WindowsFormsApplication26 Group3: WindowsFormsApplication26\WindowsFormsApplication26.csproj Group4: {25F0453B-9C88-4C9E-AG6A-97873BB6EA23}

Answer 1

我认为你的方法应该正确工作但是为了从解决方案文件中提取信息，我们通过访问“Microsoft.Build”的内部技术使用以下方法。命名空间。由于相应的框架功能被标记为internal，因此有必要

public struct ProjectData
{
    public string Name;
    public string Guid;
    public string Path;
}

public static List<ProjectData> GetProjectsInSolution(string pathToSolutionFile)
{
    Type parserType = Type.GetType("Microsoft.Build.Construction.SolutionParser, Microsoft.Build, Version=4.0.0.0, Culture=neutral, PublicKeyToken=b03f5f7f11d50a3a", false, false);

    ConstructorInfo constructorInfo = parserType.GetConstructors(BindingFlags.NonPublic | BindingFlags.Instance).First();
    object solutionParser = constructorInfo.Invoke(null);

    PropertyInfo solutionFileProperty = parserType.GetProperty("SolutionFile", BindingFlags.NonPublic | BindingFlags.Instance);
    solutionFileProperty.SetValue(solutionParser, pathToSolutionFile);

    MethodInfo parserMethod = parserType.GetMethod("ParseSolutionFile", BindingFlags.NonPublic | BindingFlags.Instance);
    parserMethod.Invoke(solutionParser, null);

    PropertyInfo projectInfo = parserType.GetProperty("Projects", BindingFlags.NonPublic | BindingFlags.Instance);
    object[] projects = projectInfo.GetValue(solutionParser) as object[];

    Type projectType = Type.GetType("Microsoft.Build.Construction.ProjectInSolution, Microsoft.Build, Version=4.0.0.0, Culture=neutral, PublicKeyToken=b03f5f7f11d50a3a", false, false);

    PropertyInfo nameInfo = projectType.GetProperty("ProjectName", BindingFlags.NonPublic | BindingFlags.Instance);
    PropertyInfo guidInfo = projectType.GetProperty("ProjectGuid", BindingFlags.NonPublic | BindingFlags.Instance);
    PropertyInfo pathInfo = projectType.GetProperty("RelativePath", BindingFlags.NonPublic | BindingFlags.Instance);

    List<ProjectData> projectData = new List<ProjectData>();

    if (projects != null)
    {
        foreach (object project in projects)
        {
            projectData.Add(new ProjectData()
            {
                Name = nameInfo.GetValue(project) as string,
                Guid = guidInfo.GetValue(project) as string,
                Path = pathInfo.GetValue(project) as string
            });
        }
    }

    return projectData;
}

与.slnFile相关的问题

1 个答案: