Question

#HangMan - 2014
import random
import time

secret = ""
dash = ""

def create_hangman():
    #List of words, pick a word, then set it to a var
    words = ["soccer", "summer", "windows", "lights", "nighttime", "desktop", "walk"]
    d = random.randint(0, 6)

    #Tell the compiler we want the global secret var
    global secret
    #Change the global secret v to a string while we choose the word
    secret = str(words[d])

    #The blank spaces. Find how many letters the word is and replace it with underscores
    create_hangman.dash = "_ " * len(secret)

    #Print the hangman
    print('''
            O
        ----|----   
            |
           [|]
           [ ]

    ''', create_hangman.dash, secret)

def guess(letter):
    #If the guess is in the word...
    if(letter in secret):
        print("Congratulations!", letter, " was found!")
        edit_blanks(letter)
    else:
        print(letter, "is not in the secret word!")

def edit_blanks(letter):
    #BUG: If there is more then one letter it shows -1. Make an if statement to see if there is more than one letter in it
    #Need to find what number the letter is in the secret word
    word_location = secret.find(letter)
    #Now from the location of the correct word find the location in the dashs
    dash_letter = create_hangman.dash[word_location * 2]
    #Replace the correct dash to the letter
    create_hangman.dash = create_hangman.dash.replace(dash_letter, letter)
    #BUG: This replaces all _'s not just the one Ex: from _ _ _ _ _ to a a a a a when it should be _ a _ _ _ 
    print(create_hangman.dash)

def wrong_word(letter):
    #TODO: Make a peice on the hangman
    print("")

name = input("Whats your name? ")
print("Hey", name, "welcome to HangMan 1.2")
create_hangman()
think = input("Pick a letter: ")
guess(think)

好吧，我上面的代码有问题。这是我的第一个python项目，我在这里有一个问题：

def edit_blanks(letter):
    #BUG: If there is more then one letter it shows -1. Make an if statement to see if there is more than one letter in it
    #Need to find what number the letter is in the secret word
    word_location = secret.find(letter)
    #Now from the location of the correct word find the location in the dashs
    dash_letter = create_hangman.dash[word_location * 2] #I use * 2 because there is a space _ _
    #Replace the correct dash to the letter
    create_hangman.dash = create_hangman.dash.replace(dash_letter, letter)
    #BUG: This replaces all _'s not just the one Ex: from _ _ _ _ _ to a a a a a when it should be _ a _ _ _ 
    print(create_hangman.dash)

我没有从中得到错误，但它没有做我需要它做的事情。我试图让它用一个字母替换_ _ _ _ _，以防它们从_ _ _ _ _ _到_ u _ _ _ 得到正确的字母。我认为这会解决这个问题，而不是使用dash_letter = create_hangman.dash [word_location * 2]来获取''，我会得到它的索引号。但我不知道怎么做，有什么想法吗？感谢

Answer 1

为什么不制作下划线列表，然后用索引替换它们。然后，当您必须将列表打印到控制台时，只需使用''.join(list)。也许像你这样的移除破折号功能？我所做的就是首先创建一个与单词长度相同的下划线空白列表，然后只需运行remove_dash函数即可替换任何需要替换的字母。

word = 'telephone'
hangman_dash = ['_' for x in range(len(word))]
def remove_dash(letter):
    for i in range(len(word)):
        if word[i] == letter:
            hangman_dash[i] = letter

remove_dash('e')
print hangman_dash
print ''.join(hangman_dash)

当我只需要替换一个时，Python正在替换所有_

1 个答案: