我的代码的elif语句中出现了无效的语法错误。我做错了什么?
# define the functions for each math operation
#
def add (a, b) :
return a + b
def subtract (a, b) :
return a - b
def multiply (a, b) :
return a * b
def divide (a, b) :
return a / b
def remainder (a, b) :
return a % b
def welcome_message ( first_name ) :
print ("Hi ", first_name, " " ". Welcome to Project 3!")
welcome_message("Prof. Shah")
loop = 1
while loop ==1:
print ("Select operation.")
print ("1. Add")
print ("2. Subtract")
print ("3. Multiply")
print ("4. Divide")
print ("5. Remainder")
choice = input("Enter choice :")
num1 = int(input |"Please enter your first number: ")
num2 = int(input |"Please enter your second number: ")
if choice == '1' :
print(num1, "+", num2, "=", add (num1,num2)
elif choice == '2' :
print(num1, "-", num2, "=", subtract (num1,num2)
elif choice == '3' :
print(num1, "*", num2, "=", multiply (num1,num2)
elif choice == '4' :
print(num1, "/", num2, "=", divide (num1,num2)
elif choice == '5' :
print(num1, "%", num2, "=", remainder (num1,num2)
答案 0 :(得分:2)
if choice == '1' :
print(num1, "+", num2, "=", add(num1,num2))
elif choice == '2' :
print(num1, "-", num2, "=", subtract(num1,num2))
...
您的缩进似乎已关闭,并且您在每个打印声明的末尾都缺少一个右括号。
答案 1 :(得分:0)
if choice == '1' :
print(num1, "+", num2, "=", add (num1,num2)
elif choice == '2' :
print(num1, "-", num2, "=", subtract (num1,num2)
elif choice == '3' :
print(num1, "*", num2, "=", multiply (num1,num2)
elif choice == '4' :
print(num1, "/", num2, "=", divide (num1,num2)
elif choice == '5' :
print(num1, "%", num2, "=", remainder (num1,num2)
问题在这里。如果"如果"阻止即将进行处理,然后你必须先从ifif开始。喜欢:
if choice == '1' :
print(num1, "+", num2, "=", add (num1,num2)
elif choice == '2' :
print(num1, "-", num2, "=", subtract (num1,num2)
elif choice == '3' :
print(num1, "*", num2, "=", multiply (num1,num2)
elif choice == '4' :
print(num1, "/", num2, "=", divide (num1,num2)
elif choice == '5' :
print(num1, "%", num2, "=", remainder (num1,num2)