Question

当2d阵列没有任何＆＃34; X＆＃34;时，我想让我的程序退出。留在里面。我用＆＃34; 1＆＃34;替换它们。用户输入（x和y）。我该怎么办？而且，如果您在我的代码中发现错误，如果您能指出这一点，我将非常感激。

import java.util.Scanner;

public class MultiArrays {

    public static void main(String[] args) {

        MultiArrays mu = new MultiArrays();
        String firstArray[][] = { { "X", "X", "X" }, { "X", "X", "X" } };
        boolean quit = true;

        do {
            mu.display(firstArray);
            mu.pickNum(firstArray);
            mu.display(firstArray);
            System.out.println();
        } while (quit == true);
    }

    public void display(String x[][]) {
        for (int row = 0; row < x.length; row++) {
            for (int col = 0; col < x[row].length; col++) {
                System.out.print(x[row][col] + "\t");
            }
            System.out.println();
        }
    }

    public void pickNum(String x[][]) {

        System.out.println("Pick row number (0-1) >");
        @SuppressWarnings("resource")
        Scanner scan = new Scanner(System.in);
        int num = scan.nextInt();
        System.out.println("Pick column number (0-2) >");
        int num2 = scan.nextInt();
        x[num][num2] = "1";

    }

}

Answer 1

将quit变量设置为true，您可以执行以下操作：

boolean quit=true;
do {   // no matter what value quit has, we would loop at least once
     mu.display(firstArray);
     mu.pickNum(firstArray);
     mu.display(firstArray);
     System.out.println();

     for (int row = 0; row < firstArray.length; row++) {
        for (int col = 0; col < firstArray[row].length; col++) {
            quit &= !firstArray[row][col].equalsIgnoreCase("X");   // do boolean AND while checking each element if it is something else than "X"
        }
     }
  } while (!quit);  // stop looping when quit is set to true

该行

quit &= !firstArray[row][col].equalsIgnoreCase("X");
quit = quit & !firstArray[row][col].equalsIgnoreCase("X")  // the same but longer

当且仅当所有元素 true
时，
评估为"X"

当2d数组没有剩下特定元素时退出程序

1 个答案: