Question

这是代码：

<?php
include "../include/koneksi_db.php";
include "../user/link.php";     
$query=mysql_query("SELECT * FROM admin WHERE id=$id", $konek);
$hasil=mysql_fetch_array($query);
$id  =$hasil['id'];
$user=$hasil['username'];
$pass=$hasil['password'];
$hak =$hasil['hak_akses'];
?>

问题：如何解决这个问题：Nocticce：未定义的变量：第5行的C：.... \ ed_user.php中的id

Answer 1

不确定我是否理解正确：这个？

<?php
include "../include/koneksi_db.php";
include "../user/link.php";

 $check_the_query = "SELECT * FROM admin WHERE id='".$id."'";
$query=mysql_query(, $konek);

while($hasil=mysql_fetch_array($query)){
    $id  =$hasil['id'];
    $user=$hasil['username'];
    $pass=$hasil['password'];
    $hak =$hasil['hak_akses'];

    echo "id -> ".$id."<br>";
    echo "user -> ".$id."<br>";
    echo("<br>");
}

?>

我无法定义变量来更新我的数据库

1 个答案: