Question

从mySQL中获取数据并通过php生成json，如下所示：

while ($row = mysql_fetch_array($result)) {
     $menu[] = array("type"=>"FeatureCollection", 
                    "features" => [array("type"=>"Feature",
                                         "geometry"=>array("type"=>"Point",
                                                           "coordinates"=>[-77.034084142948,38.909671288923]),
                                         "properties"=>array("phone"=>"041","city"=>"Faisalabad","country"=>"Pakistan"))]       
        );
}   $json =  json_encode($menu); 
    echo $json;

，结果如下：

[
{
    "type": "FeatureCollection",
    "features": [
        {
            "type": "Feature",
            "geometry": {
                "type": "Point",
                "coordinates": [
                    -77.034084142948,
                    38.909671288923
                ]
            },
            "properties": {
                "phone": "041",
                "city": "Faisalabad",
                "country": "Pakistan"
            }
        }
    ]
},
{
    "type": "FeatureCollection",
    "features": [
        {
            "type": "Feature",
            "geometry": {
                "type": "Point",
                "coordinates": [
                    -77.034084142948,
                    38.909671288923
                ]
            },
            "properties": {
                "phone": "041",
                "city": "Faisalabad",
                "country": "Pakistan"
            }
        }
    ]
},
{
    "type": "FeatureCollection",
    "features": [
        {
            "type": "Feature",
            "geometry": {
                "type": "Point",
                "coordinates": [
                    -77.034084142948,
                    38.909671288923
                ]
            },
            "properties": {
                "phone": "041",
                "city": "Faisalabad",
                "country": "Pakistan"
            }
        }
    ]
}]

正如你所看到{“type”：“FeatureCollection”，“features”：[{...}]}正在重复三次，我希望它出现在开头，就像跟着json一样，所以{ “type”：“FeatureCollection”，“features”：[{I WANT LOOP HERE only}}}：我想要这个结果：

[
{
    "type": "FeatureCollection",
    "features": [
        {
            "type": "Feature",
            "geometry": {
                "type": "Point",
                "coordinates": [
                    -77.034084142948,
                    38.909671288923
                ]
            },
            "properties": {
                "phone": "041",
                "city": "Faisalabad",
                "country": "Pakistan"
            }
        },
        {
            "type": "Feature",
            "geometry": {
                "type": "Point",
                "coordinates": [
                    -77.034084142948,
                    38.909671288923
                ]
            },
            "properties": {
                "phone": "041",
                "city": "Faisalabad",
                "country": "Pakistan"
            }
        },
        {
            "type": "Feature",
            "geometry": {
                "type": "Point",
                "coordinates": [
                    -77.034084142948,
                    38.909671288923
                ]
            },
            "properties": {
                "phone": "041",
                "city": "Faisalabad",
                "country": "Pakistan"
            }
        }
    ]
}]

请帮助我一直在尝试太多。感谢

Answer 1

那么，为什么你要继续重复＆＃34; FeatureCollection＆＃34;在while循环中，如果你只需要一次？

我想你想要这样的东西：

$menu = array();
features = array();
$menu['type'] = 'FeatureCollection';

while ($row = mysql_fetch_array($result)) {
     $features[] = array("type"=>"Feature",
                       //Other features here
      );
}

$menu['features'] = $features;

Answer 2

在$menu数组中，您应该定义值为type的键FeatureCollection和键features。在你的while循环中执行以下操作：

$menu = array(
    'type' => 'FeatureCollection',
    'features' => array()
);
while ($row = mysql_fetch_array($result)) {
    $menu[`features`][] = array(...);
}

数组结构帮助在php中生成json

2 个答案: