日期差异仅考虑年月日

Question

我想在php中考虑年，月，日来计算日期差异。现在程序计算考虑所有日期时间对象参数的日期差异。

$DTObj = new DateTime();
$pdate = DateTime::createFromFormat("ymd", 141118);
$diff = $DTObj->diff($pdate);
$dday = $diff->format("%a");

我怎样才能实现这一目标。

Answer 1

阅读并试试这个：

# create DateTime object with time at 00:00:00
$from = new DateTime('today'); 

# create DateTime object from ymd format
# format character ! resets all fields (year, month, ...) to the Unix Epoch and then sets the inputed date
$to = DateTime::createFromFormat('!ymd', '141118');

# calculate difference between $from and $to and return DateInterval object
$diff = $from->diff($to);

# echo difference of total number of days
echo $diff->format('%a');

demo