Question

我的网站托管在000webhost中，我已经在文件管理器中创建了一个名为“Uploaded CVs”的目录，但是我收到了这个错误：

警告：move_uploaded_file（）[function.move-uploaded-file]：open_basedir限制生效

php代码：

<?php 
$file_result = "";

if ($_FILES["file"]["error"] >0)
{
    $file_result .="File did not upload! Try again!";
    $file_result .="Error occured: " . $_FILES["file"]["error"] . "<br>";
    }else{

    $file_result.=
    "Upload: " . $_FILES["file"]["name"] . "<br>" .
    "Type: " . $_FILES["file"]["type"] . "<br>" .
    "Size: " . ($_FILES["file"]["size"] / 1024 ). " Kb<br>" .
    "Temp file: " . $_FILES["file"]["tmp_name"] . "<br>";

    move_uploaded_file($_FILES["file"]["tmp_name"],
    $_SERVER['DOCUMENT_ROOT'] . "/Uploaded CVs/" . $_FILES["file"]["name"]);

    $file_result .= "CV Uploaded Successfully!";


}
?>

任何想法都是正确的道路吗？感谢。

Answer 1

对于此示例，文件夹与文件位于同一路径中。

<?php 
$file_result = "";

if ($_FILES["file"]["error"] >0)
{
    $file_result .="File did not upload! Try again!";
    $file_result .="Error occured: " . $_FILES["file"]["error"] . "<br>";
    }else{

    $file_result.=
    "Upload: " . $_FILES["file"]["name"] . "<br>" .
    "Type: " . $_FILES["file"]["type"] . "<br>" .
    "Size: " . ($_FILES["file"]["size"] / 1024 ). " Kb<br>" .
    "Temp file: " . $_FILES["file"]["tmp_name"] . "<br>";

    if (move_uploaded_file($_FILES["file"]["tmp_name"], "Uploaded CVs/".$_FILES["file"]["name"])) {
       $file_result .= "CV Uploaded Successfully!";
    } else {
       $file_result .= "Error trying to uploas the file";
    }    
}
?>

看看this question

将文件上载到服务器的正确路径

1 个答案: