在我的某台设备上,以下代码无法让我的视频显示在图库中:
File file = new File(path);
Uri uri = Uri.fromFile(file);
Intent scanFileIntent = new Intent(Intent.ACTION_MEDIA_SCANNER_SCAN_FILE, uri);
activity.sendBroadcast(scanFileIntent);
所以我明确使用scanFile
:
android.media.MediaScannerConnection.scanFile(activity, new String[]{file.getAbsolutePath()},
new String[]{"video/" + mMimeType}, null);
当我的视频是xxx.mpeg4时,mMimeType
的值是mp4,结果是视频可以出现在MediaStore中,但我以后不能获得持续时间(返回值始终为0) )。需要帮助。
public static long[] getVideoDetail(Context context, Uri uri) {
long[] result = new long[] {DEFAULT_VIDEO_FRAME_WIDTH, DEFAULT_VIDEO_FRAME_HEIGHT, -1};
if(uri == null || (!ContentResolver.SCHEME_CONTENT.equals(uri.getScheme()))) {
return result;
}
String[] projection = new String[] {MediaStore.Video.Media.RESOLUTION, MediaStore.Video.VideoColumns.DURATION};
Cursor cursor = null;
boolean success = false;
try {
cursor = context.getContentResolver().query(uri, projection, null, null, null);
if (cursor.moveToFirst()) {
String resolution = cursor.getString(0);
if(!StringUtils.isEmpty(resolution)) {
int index = resolution.indexOf('x');
result[0] = Integer.parseInt(resolution.substring(0, index));
result[1] = Integer.parseInt(resolution.substring(index + 1));
if(result[0] != 0 && result[1] != 0) {
success = true;
}
if(result[0] > result[1]) {
swap(result, 0, 1);
}
}
result[2] = cursor.getLong(1);
if(result[2] >= 0 && success) {
success = true;
} else {
success = false;
}
}
if (null != cursor) {
cursor.close();
}
}
catch (Exception e) {
// do nothing
} finally {
try {
if (null != cursor) {
cursor.close();
}
} catch (Exception e2) {
// do nothing
}
}
if (!success) {
try {
ContentResolver contentResolver = context.getContentResolver();
String selection = MediaStore.Images.Media._ID + "= ?";
String id = uri.getLastPathSegment();
String[] selectionArgs = new String[]{ id };
cursor = contentResolver.query(MediaStore.Video.Media.EXTERNAL_CONTENT_URI, projection, selection, selectionArgs, null);
if (cursor.moveToFirst()) {
String resolution = cursor.getString(0);
if(!StringUtils.isEmpty(resolution)) {
int index = resolution.indexOf('x');
result[0] = Integer.parseInt(resolution.substring(0, index));
result[1] = Integer.parseInt(resolution.substring(index + 1));
if(result[0] > result[1]) {
swap(result, 0, 1);
}
}
result[2] = cursor.getLong(1);
}
if (null != cursor) {
cursor.close();
}
} catch (Exception e) {
// do nothing
} finally {
try {
if (cursor != null) {
cursor.close();
}
} catch (Exception e) {
// do nothing
}
}
}
if(result[0] <= 0) {
result[0] = DEFAULT_VIDEO_FRAME_WIDTH;
}
if(result[1] <= 0) {
result[1] = DEFAULT_VIDEO_FRAME_HEIGHT;
}
return result;
}
答案 0 :(得分:1)
正如我在您的代码中看到的那样,您在预测中要求持续时间
String[] projection = new String[] {MediaStore.Video.Media.RESOLUTION, MediaStore.Video.VideoColumns.DURATION};
现在您只需要从cursor
中检索它,如下所示:
long timeInMs = cursor.getLong(cursor.getColumnIndex(MediaStore.Video.VideoColumns.DURATION));
答案 1 :(得分:0)
从MediaPlayer获得帮助:
MediaPlayer mp = new MediaPlayer();
try {
mp.setDataSource(context, Uri.parse(uri));
} catch (IOException e) {
Log.d("-MS-","Cannot parse url");
e.printStackTrace();
}
int duration= mp.getDuration();
String[] projection = new String[] {MediaStore.Video.Media.RESOLUTION,duration};
我总是通过MediaPlayer获得持续时间。