Question

我创建了一个ArrayList来存储客户的名字。然后我在列表中填写了一些名字。

现在我想要求用户输入一个字母，然后找到 以输入的字母开头的所有名称 和 包含输入字母的所有名称。

这就是我现在所处的位置：

    package costomersearching;

import java.util.ArrayList;
import java.util.Scanner;

public class CostomerSearching {

    public static void main(String[] args) {
        ArrayList<String> customerName = new ArrayList();
        Scanner input = new Scanner(System.in);
        customerName.add("Sara");
        customerName.add("John");
        customerName.add("Miami");
        customerName.add("Mart");
        customerName.add("Alex");

        System.out.println("Customer List: \n" + customerName);
        System.out.println("Search Customer by letter: ");
        String letter = input.next();
        //show the name containg the letter starting as the first letter
        //Show the name containing the letetr.
    }

}

Answer 1

您要搜索的方法是startsWith（String）并包含String类的（CharSequence）。此外，这样它也可以使用多个字母。

只需遍历您的客户列表并检查名称。只要找到匹配的产品，就可以将其添加到之后要打印给用户的客户列表中。

String searchterm = "s"; // You read the string from console

// Existing customers
ArrayList<String> customerNames = new ArrayList<String>();

// A list of customer names starting with the search term
ArrayList<String> matchesStarting = new ArrayList<String>();

// A list of customer names containing the search term
ArrayList<String> matchesContaining = new ArrayList<String>();

// Iterate over customers and check for each one if it matches the search term
for(String customer: customerNames) {

    // If it starts with the search term, add it to the list of start matches
    if(customer.startsWith(searchterm))
        matchesStarting.add(customer);

    // If it contains the search term, add it to the list of start matches
    if(customer.contains(searchterm))
        matchesContaining.add(customer);
 }

Answer 2

简单地遍历您的ArrayList并搜索正确的名称。你可以这样做：

//show names containing the letter starting as the first letter
for(String i : costumerName) {
    if(i.startsWith(letter)) System.out.println(i);
}

//show names containing the letter
for(String i : costumerName) {
    if(i.contains(letter)) System.out.println(i);
}

希望这会有所帮助：）

Answer 3

import java.util.ArrayList;
import java.util.List;
import java.util.Scanner;


public class TestStack {
    public static void main(String[] args) {
        Scanner input = null ;
        try{
            ArrayList<String> customerName = new ArrayList<>();
            input = new Scanner(System.in);
            customerName.add("Sara");
            customerName.add("John");
            customerName.add("Miami");
            customerName.add("Mart");
            customerName.add("Alex");

            System.out.println("Customer List: \n" + customerName);
            System.out.println("Search Customer by letter: ");
            String letter = input.next();

            List<String> searchResult = new ArrayList<>();
            for (String string : customerName) {
                  if(string.contains(letter))
                     searchResult.add(string);
             }

            List<String> searchResultStartsWithSpecifiedLetters = new ArrayList<>();
            for (String string : customerName) {
                if(string.startsWith(letter))
                    searchResult.add(string);
            }

            System.out.println("Displaying result containing entered letters");
            // Displays result containing those letters
            for (String string : searchResult) {
                System.out.println(string);
            }

            System.out.println("Displaying result starts with entered letters");
            // Displays result starts with those letters
            for (String string : searchResultStartsWithSpecifiedLetters) {
                System.out.println(string);
            }
        }finally{
            input.close();
        }
    }
}

如何找到以用户输入的字母开头的名称？

3 个答案: