Question

我正在尝试建立一个由10x10网格组成的战场。

以下是我的代码：

SHIP_HASH = { submarine: 2, destroyer: 3, destroyer: 3, cruiser: 4, aircraftcarrier: 5,}

def print_results
  board_layout = Array.new(10, " ").map{|row| Array.new(10, " ")}
  row_label = ["0", "1", "2", "3", "4", "5", "6", "7", "8", "9"]
  column_label = [" ", "0", "1", "2", "3", "4", "5", "6", "7", "8", "9"]
end

print print_results

我收到了输出：

[" ", "0", "1", "2", "3", "4", "5", "6", "7", "8", "9"]

我想要的是生成如下输出，但我不知道错误是什么。 0 1 2 3 4 5 6 7 8 9 0 . . . . . . . . . . 1 . . . . . . . . . . 2 . . . . . . . . . . 3 . . . . . . . . . . 4 . . . . . . . . . . 5 . . . . . . . . . . 6 . . . . . . . . . . 7 . . . . . . . . . . 8 . . . . . . . . . . 9 . . . . . . . . . .

Answer 1

所以在ruby中，在方法中评估的最后一件事是返回的内容。所以在你的print results中，评估的最后一件事就是column_label的分配，这就是你看到的内容。

以下是代码，请注意在某些情况下使用print，在其他情况下使用puts，因为它们执行不同的操作：

SHIP_HASH = { submarine: 2, destroyer: 3, destroyer: 3, cruiser: 4, aircraftcarrier: 5,}

def print_results
  board_layout = Array.new(10, ".").map{|row| Array.new(10, ".")}
  row_label = ["0", "1", "2", "3", "4", "5", "6", "7", "8", "9"]
  column_label = ["0", "1", "2", "3", "4", "5", "6", "7", "8", "9"]

  print "\t"
  print row_label.join("\t")
  puts
  board_layout.each_with_index do |row, i|
    print column_label[i]
    print "\t"
    print row.join("\t")
    puts
  end
end

print_results

输出：

    0   1   2   3   4   5   6   7   8   9
0   .   .   .   .   .   .   .   .   .   .
1   .   .   .   .   .   .   .   .   .   .
2   .   .   .   .   .   .   .   .   .   .
3   .   .   .   .   .   .   .   .   .   .
4   .   .   .   .   .   .   .   .   .   .
5   .   .   .   .   .   .   .   .   .   .
6   .   .   .   .   .   .   .   .   .   .
7   .   .   .   .   .   .   .   .   .   .
8   .   .   .   .   .   .   .   .   .   .
9   .   .   .   .   .   .   .   .   .   .

如果您对此有任何疑问，请与我们联系。

Answer 2

SHIP_HASH = { submarine: 2, destroyer: 3, destroyer: 3, cruiser: 4, aircraftcarrier: 5,}

def print_results
  board_layout = Array.new(10, ".").map{|row| Array.new(10, ".")}
  row_label = ["0", "1", "2", "3", "4", "5", "6", "7", "8", "9"]
  column_label = ["0", "1", "2", "3", "4", "5", "6", "7", "8", "9"]

print "\t"
print row_label.join("\t")
puts
board_layout.each_with_index do |row, i|
  print column_label[i]
  print "\t"
  print row.join("\t")
  puts
  end
end

print_results

在Ruby中创建战场网格

2 个答案: