我有一个js文件(下面),其中每个函数返回2个结果(Step1和Step2)。我需要将这些结果放到像...这样的格式中。
“混合”+(Step1 productType)+“with”+(Step1 peroxide)+“。”+(Step1计时)
使用“+(Step2 productType)+”,将“+(Step2 toneCalc)+”与“+(Step2 peroxide)+”混合。 “+(Step2计时)
将这些结果转换为上述格式的最佳方法是什么? 我知道如何处理单个值,但对函数中包含的多个函数不太确定。
由于
function doubleprocess(type) {
function productType() {
var step1;
var step2;
if (type == "light") {
step1 = "lightner";
step2 = "demi-color";
} else {
step1 = "demi-color";
step2 = "demi-color";
}
return step1, step2;
}
function toneCalc() {
var step1;
var step2;
if (type == "light") {
step1 = "light gold";
} else if (type == "dark") {
step1 = "80% gold with 20% red"
} else {
step1 = "another tone";
}
step2 = "neutral";
return step1, step2;
}
function peroxide() {
var step1;
var step2;
if (type == "light") {
step1 == "20V/6% peroxide";
} else if (type == "dark") {
step1 = "something else";
} else {
step1 = "Do something.";
}
step2 = "Do something else.";
return step1, step2;
}
function level() {
var step1 = "";
var step2;
if (type == "dark") {
step1 = "Do something.";
} else {
step1 = "Do Nothing.";
};
step2 = "Do something.";
return step1, step2;
}
function timing() {
var step1;
var step2;
if (type == "light") {
step1 == "Do something.";
step2 = "Do something.";
} else if (type == "dark") {
step1 = "Do something.";
step2 = "Do something.";
} else {
step1 = "Do something.";
step2 = "Do something.";
}
return step1, step2;
}
}
答案 0 :(得分:3)
您无法从函数返回多个变量。但是你可以返回一个对象。
function peroxide() {
var step1;
var step2;
if (type == "light") {
step1 == "20V/6% peroxide";
} else if (type == "dark") {
step1 = "something else";
} else {
step1 = "Do something.";
}
step2 = "Do something else.";
var rtn = new Object();
rtn.step1 = step1;
rtn.step2 = step2;
return rtn;
}
答案 1 :(得分:1)
Javascript函数只返回一个值。尝试返回一个对象或数组。