Question

我正在处理一个搜索表单，我想通过网址中的值发布搜索结果。我无法获取包含参数的网址。如果我在视图中键入值（如果不是$ this-＆gt; search_zip I键'12345'），它们将发布。目前，除了URL之外，搜索按预期工作。我目前从表单中获取搜索条件，我是否需要更改控制器设置以从网址获取它们？如果是这种情况我将如何过滤？

最终我想要我的网址阅读：

results / 12345 / otherparam

我目前正在

结果

无论我键入表单的变量是什么。

模块配置

return array(
    'router' => array(
        'routes' => array(
            'home' => array(
                'type' => 'segment',
                'options' => array(
                    'route'    => '/',
                    'constraints' => array(
                                'action'     => '[a-zA-Z][a-zA-Z0-9_-]*',
                    ),
                    'defaults' => array(
                        'controller' => 'Application\Controller\Index',
                        'action'     => 'index',
                    ),
                ),
                'may_terminate' => true, //START OF CHILD ROUTES
                'child_routes' => array(
                'results' => array(
                    'type' => 'segment',
                    'options' => array(
                        'route' => 'results[/:search_zip][/:search_industry]',
                        'defaults' => array(
                            'controller' => 'Application\Controller\Index',
                            'action'     => 'results',

结果视图

$form->setAttribute('action', $this->url(
 'home/results',
 array(
     'action' => 'results',
     'search_zip'=> $this->search_zip,
     'search_industry' => 'industry_name'

    echo $this->formRow($form->get('industry_name'));//this is the form field
    echo $this->formSubmit($form->get('submit'));

控制器

 //beginning of the results action
    $request = $this->getRequest();   
             $form = new SearchForm($dbAdapter);  
             if ($request->isPost()) {
                 $search = new MainSearch();          
                 $form->setInputFilter($search->getInputFilter());                
                 $form->setData($request->getPost());  
                 if ($form->isValid()) {

在我的resultsAction结束时，我返回表单和结果（根据专辑示例）

     return array(
        'form' => $form,
        'pros' => $fetchPros,
              );

谢谢你，中号

Answer 1

//This will give you an array containing your desired parameters
$params = $this->params()->fromRoute();
//Then you can simply use them like this
$search_zip = $params['search_zip'];
$search_industry  = $params['search_industry'];

网址参数问题

1 个答案: