我需要为分数计算器编写一个代码,可以对两个分数进行加,减,乘和除。我有这个代码,并收到错误消息
Exception in thread "main" java.lang.StringIndexOutOfBoundsException: String index out of range: -1
at java.lang.String.substring(Unknown Source)
at Calculator.run(Calculator.java:24)
at Calculator.main(Calculator.java:13)
我知道错误信息给了我需要修复的地方,但我无法弄清楚我做错了什么。我仍然是Java的新手,所以它可能是一个非常简单的解决方案。
提前谢谢。
import java.util.*;
public class Calculator {
public static void main(String[] args) {
System.out.println("Please enter two fractions to add, subtract, multiply, or divide\nor\nType 'quit' to exit the program.");
Boolean on = true;
Scanner console = new Scanner(System.in);
while (on) {
String input = console.nextLine();
if (input.equalsIgnoreCase("quit")) {
on = false;
} else
System.out.println(run(input));
}
}
public static String run(String input) {
int indexOfSecondSpace = 0;
int indexOfOperation = 0;
String firstNumber = "0";
String secondNumber = "0";
int beginning = input.indexOf(" ") + 1;
int end = input.indexOf(" ", input.indexOf(" "));
String operator = input.substring(beginning, end);
if (input.contains("+") == true) {
indexOfOperation = input.indexOf("+");
} else if (operator.equals("-")) {
indexOfOperation = input.indexOf("-");
} else if (operator.equals("*")) {
indexOfOperation = input.indexOf("*");
} else if (operator.equals("/")) {
indexOfOperation = input.indexOf("/");
}
firstNumber = (input.substring(input.indexOf(" ")));
secondNumber = (input.substring(input.indexOf(" ") + 1));
int a = 0;
int b = 0;
int c = 0;
int d = 0;
if (firstNumber.contains("/")) {
a = Integer.parseInt(firstNumber.substring(0,firstNumber.indexOf("/")));
b = Integer.parseInt(firstNumber.substring(0),firstNumber.indexOf("/"));
} else if (!firstNumber.contains("/"))
a = Integer.parseInt(input.substring(0, input.indexOf(" ")));
b = Integer.parseInt("1");
{
if (secondNumber.contains("/")) {
c = Integer.parseInt(secondNumber.substring(secondNumber.indexOf("/")));
d = Integer.parseInt(secondNumber.substring(secondNumber.indexOf("/" + 1, secondNumber.length())));
} else if (!secondNumber.contains("/")) {
c = Integer.parseInt(secondNumber.substring(secondNumber.length()));
d = Integer.parseInt("1");
}
}
return input;
}
public static String calculate(String input, int a, int b, int c, int d){
if (input.contains ("+"))
{
System.out.println("your answer is " + (a*d + b*c)+"/" +(b*d));
}
else if (input.contains("-"))
{
System.out.println("your answer is " + (a*d - b*c)+ "/" +(b*d));
}
else if (input.contains("/"))
{
System.out.println("your answer is " + (a*d)/(b*c)+ "/" +(b*d));
}
else if (input.contains("*"))
{
System.out.println("your answer is " + (a*c) +"/" +(b*d));
}
return input;
}
}
答案 0 :(得分:2)
如果找不到字符串,String.indexOf
方法将返回-1。在这个宣传片中你有:
int beginning = input.indexOf(" ") + 1;
int end = input.indexOf(" ", input.indexOf(" "));
导致
int beginning = input.indexOf(" ") + 1; // = -1 + 1 = 0
int end = input.indexOf(" ", input.indexOf(" ")); // input.indexOf(" ", -1); ERROR!
你很可能是:
int beginning = input.indexOf(" ") + 1; // = -1 + 1 = 0
int end = input.indexOf(" ", beginning ); // input.indexOf(" ", 0); Great job!
答案 1 :(得分:0)
ug_的答案是对的..顺便说一句,你的方法run()包含很多错误(我试图运行它)
我认为固定版本对你有用..这里是:(检查substring()方法;))
public static String run(String input) {
int indexOfSecondSpace = 0;
int indexOfOperation = 0;
String firstNumber = "0";
String secondNumber = "0";
int beginning = input.indexOf(" ") + 1;
int end = input.indexOf(" ", beginning);
String operator = input.substring(beginning, end);
if (input.contains("+") == true) {
indexOfOperation = input.indexOf("+");
} else if (operator.equals("-")) {
indexOfOperation = input.indexOf("-");
} else if (operator.equals("*")) {
indexOfOperation = input.indexOf("*");
} else if (operator.equals("/")) {
indexOfOperation = input.indexOf("/");
}
firstNumber = (input.substring(0, input.indexOf(" ")));
secondNumber = (input.substring(beginning + 1));
int a = 0;
int b = 0;
int c = 0;
int d = 0;
if (firstNumber.contains("/")) {
a = Integer.parseInt(firstNumber.substring(0,firstNumber.indexOf("/")));
b = Integer.parseInt(firstNumber.substring(0,firstNumber.indexOf("/")));
} else if (!firstNumber.contains("/"))
a = Integer.parseInt(input.substring(0, input.indexOf(" ")));
b = Integer.parseInt("1");
{
if (secondNumber.contains("/")) {
c = Integer.parseInt(secondNumber.substring(secondNumber.indexOf("/")+1));
d = Integer.parseInt(secondNumber.substring(secondNumber.indexOf("/")+1));
} else if (!secondNumber.contains("/")) {
c = Integer.parseInt(secondNumber.substring(secondNumber.length()));
d = Integer.parseInt("1");
}
}
return input;
}