Question

我正在使用H2嵌入式数据库实现单元测试。当我在表中插入一个条目时，我能够使用本机SQL查询检索该条目，但不能使用HQL查询。主键查找也可以通过JPA EntityManager接口工作。我使用Hibernate作为持久性提供程序。

配置：

<bean id="hibernateJpaVendorAdapter"
    class="org.springframework.orm.jpa.vendor.HibernateJpaVendorAdapter"
    p:showSql="true" p:generateDdl="false" p:databasePlatform="org.hibernate.dialect.H2Dialect"    />

    <bean id="entityManagerFactory"
    class="org.springframework.orm.jpa.LocalContainerEntityManagerFactoryBean"
    p:dataSource-ref="dataSource" p:jpaVendorAdapter-ref="hibernateJpaVendorAdapter"
    p:persistenceUnitName="AMgSAdapter" p:packagesToScan="com.hcsc.amgs.adapter.domaindto">
    <property name="jpaProperties">
        <props>
            <prop key="hibernate.hbm2ddl.auto">create</prop>
        </props>
    </property>
    <property name="jpaPropertyMap">
        <map>
            <entry key="hibernate.ejb.interceptor" value="com.hcsc.amgs.adapter.dao.hibernate.interceptor.AuditableFieldInterceptor" />
        </map>
    </property>
</bean>

测试用例：

 @Test
    @Transactional(value="transactionManager",propagation = Propagation.REQUIRED)
    public void getVasPolicyMatchesTest() {
        Application application = TestDataCreationUtil.createApplication();
        entityManager.persist(application.getX834EnrollmentApplicationTransaction());
        entityManager.persist(application);
        List<Application> matches = new ArrayList<Application>();
        Query q = simpleQueryHQL();
        matches= q.getResultList();
        Application findApp = entityManager.find(Application.class, application.getId()); // this works
        Assert.assertTrue(matches.size() > 0);
    }

private Query simpleQueryHQL() {
    return entityManager.createQuery("Select app From Application app", Application.class);
}

private Query simpleQuerySQL() {
    return entityManager.createNativeQuery("Select * from Application", Application.class);
}

没有抛出异常，simpleQueryHQL（）的测试用例失败，而simpleQuerySQL（）传递

HQL不能与H2一起使用

0 个答案: