Question

如果是重复周期，需要删除第二次出现（15到15分钟），但查询总是返回全部或全部。

DECLARE @DatAteTemp DATE
DECLARE @HorAteTemp TIME

DECLARE cursor_i CURSOR FOR
SELECT DatAte, HorAte
FROM @TABLE

OPEN cursor_i
FETCH NEXT FROM cursor_i INTO @DatAteTemp, @HorAteTemp;

WHILE @@FETCH_STATUS = 0
    BEGIN

        IF  (select count(*) from @TABLE where HorAte = DATEADD(MINUTE, -15, @HorAteTemp)) > 0
        --DATEADD(MINUTE, -15, @HorAteTemp) = @HorAteTemp
        BEGIN
            DELETE FROM @TABLE WHERE CURRENT OF cursor_i
        END

        FETCH NEXT FROM cursor_i INTO @DatAteTemp, @HorAteTemp
    END

CLOSE cursor_i;
DEALLOCATE cursor_i;

另：

DECLARE @aux TIME = DATEADD(MINUTE, -15, @HorAteTemp)
IF  (select count(*) from @TABLE AS oito where oito.HorAte = @aux) > 0

Answer 1

永远不可能，因为我将其应用为：

SELECT
[...]
CROSS APPLY dbo.Function(Dat, Hor)
[...]

删除到SQL Server循环

1 个答案: