Question

我有以下服务：

    [ServiceContract]
    interface IConnectionService
    {
        [OperationContract]
        [WebInvoke(Method = "POST", UriTemplate = "GetState", BodyStyle = System.ServiceModel.Web.WebMessageBodyStyle.Wrapped), Description("")]
        State GetState();
    }

    [DataContract]
    public class State
    {
        [DataMember]
        public bool Client_1_Ok { get; set; }

        [DataMember]
        public bool Client_2_Ok { get; set; }
    }

在我的服务器端，我创建了一个State类的新实例，并设置变量只是为了看它们是否到达客户端，因为它应该

    public class Server : IConnectionService
    {
        public State GetState()
        {
            State tempState = new State();

            tempState .Client_1_Ok = true;
            tempState .Client_2_Ok = true;

            return tempState ;
        }

客户端我打开一个频道并在我的服务器端调用GetState ..到目前为止一直很好

        private IConnectionService ConnectionChannel = null;

        public State GetState()
        {
            try
            {
                ConnectionFactory = new WebChannelFactory<IConnectionService>(new Uri("http://" + this.HostIpAddress + ":" + this.Port.ToString() + "/Tes"));
                this.ConnectionChannel = ConnectionFactory.CreateChannel();

                State returnvalue = this.ConnectionChannel.GetState();

                return state;
            }
            catch (Exception e)
            {
                //Communication error
                return null;
            }
            finally
            {
                try { this.ConnectionChannel.Close(); }
                catch { this.ConnectionChannel.Abort(); }

                //dispose of the connection channel
                this.ConnectionChannel.Dispose();
                this.ConnectionChannel = null;
            }
        }

但是来自客户端的GetState调用总是返回一个布尔值为假的State实例。

在类似的帖子中，人们忘记添加DataContract和DataMember属性，但我确保添加这些属性。解决方案可能是小而愚蠢但我无法看到我搞砸的地方

Answer 1

servicecontract没有RequestFormat。在我的情况下，它需要WebMessageFormat.Json

我的ServiceContract现在看起来像这样：

    [ServiceContract]
    interface IConnectionService
    {
        [WebGet(UriTemplate = "GetState", BodyStyle = System.ServiceModel.Web.WebMessageBodyStyle.Wrapped, ResponseFormat = WebMessageFormat.Json), Description("")]
        State GetState();
    }

WCF REST服务返回空类

1 个答案: