Question

我使用以下方法来区分两个时间戳。

public static long tokenTimeDuration(String loginTime, String expiryTime){
    long diff = 0;

    Log.i("du_loginTimeFromServer",loginTime);
    Log.i("du_expiryTimeFromServer",expiryTime);
    DateFormat format = new SimpleDateFormat("EEE MMM dd HH:mm:ss a z yyyy");
    format.setLenient(false);
    Date loginDate = null;
    Date expiryDate = null;

    try {
        loginDate = (Date)format.parse(loginTime);
        Log.i("du_loginTimeAfterParsing",format.format(loginDate));
        expiryDate = (Date)format.parse(expiryTime);
        Log.i("du_expiryTimeAfterParsing",format.format(expiryDate));

        Log.i("du_loginTimeInMilliseconds",loginDate.getTime()+"");
        Log.i("du_expiryTimeInMilliseconds",expiryDate.getTime()+"");

         //in milliseconds
        diff = expiryDate.getTime() - loginDate.getTime();
        Log.i("du_tokenExpiryDuration", diff + "");

    } catch (Exception e) {
        Log.i("duEx", e.getMessage());
    }

    return diff;
}

但是在尝试使用该方法时，我得到了错误的日期转换。并记录输出如下：

12-05 19:30:45.802: I/du_loginTimeFromServer(16894): Fri Dec 05 14:00:44 PM UTC 2014
12-05 19:30:45.802: I/du_expiryTimeFromServer(16894): Fri Dec 05 17:20:44 PM UTC 2014
12-05 19:30:45.822: I/du_loginTimeAfterParsing(16894): Fri Dec 05 05:30:44 AM IST 2014
12-05 19:30:45.824: I/du_expiryTimeAfterParsing(16894): Fri Dec 05 05:50:44 AM IST 2014
12-05 19:30:45.824: I/du_loginTimeInMilliseconds(16894): 1417737644000
12-05 19:30:45.824: I/du_expiryTimeInMilliseconds(16894): 1417738844000
12-05 19:30:45.824: I/du_tokenExpiryDuration(16894): 1200000

现在，即使到期时间早于登录时间4小时，它也会产生负面差异。请帮我找到我错在哪里。

更新：如果我添加

    format.setTimeZone(TimeZone.getTimeZone("UTC"));

logcat说：

12-05 22:05:59.903: I/du_loginTimeFromServer(23574): Fri Dec 05 16:35:58 PM UTC 2014
12-05 22:05:59.903: I/du_expiryTimeFromServer(23574): Fri Dec 05 19:55:58 PM UTC 2014
12-05 22:05:59.915: I/du_loginTimeAfterParsing(23574): Fri Dec 05 00:35:58 AM UTC 2014
12-05 22:05:59.918: I/du_expiryTimeAfterParsing(23574): Fri Dec 05 00:55:58 AM UTC 2014
12-05 22:05:59.918: I/du_loginTimeInMilliseconds(23574): 1417739758000
12-05 22:05:59.919: I/du_expiryTimeInMilliseconds(23574): 1417740958000
12-05 22:05:59.919: I/du_tokenExpiryDuration(23574): 1200000

仍然不正确。

Answer 1

使用joda time

解决了此问题

相同的代码片段是：

public static long tokenTimeDuration(String loginTime, String expiryTime){
     DateTimeFormatter FMT = DateTimeFormat.forPattern("EEE MMM dd HH:mm:ss a z yyyy");
        final DateTime dt1 = new DateTime(FMT.parseDateTime(loginTime).withZone(DateTimeZone.getDefault()));
        Log.i("du_loginTimeAfterParsing",dt1.toString());

        final DateTime dt2 = new DateTime(FMT.parseDateTime(expiryTime).withZone(DateTimeZone.getDefault()));
        Log.i("du_expiryTimeAfterParsing",dt2.toString());

        long diff = dt2.getMillis() - dt1.getMillis();

        Log.i("du_tokenExpiryDuration", diff + "");    
        return diff;
}

logcat输出现在说：

12-06 06:48:22.073: I/du_loginTimeAfterParsing(10440): 2014-12-06T06:48:22.000+05:30
12-06 06:48:22.077: I/du_expiryTimeAfterParsing(10440): 2014-12-06T10:08:22.000+05:30
12-06 06:48:22.078: I/du_tokenExpiryDuration(10440): 12000000

已添加解决方案，以便其他人可以从中受益。

Answer 2

时区未对齐，服务器为UTC，解析后为IST。尝试添加这样的东西

format.setTimeZone(TimeZone.getTimeZone("UTC"));

Answer 3

只是在黑暗中拍摄（虽然我确实用此解决了类似的问题here），但尝试明确地将您的Locale添加到SimpleDateFormat中：

DateFormat format = new SimpleDateFormat("EEE MMM dd HH:mm:ss a z yyyy", Locale.US);//Or whatever your desired Locale is

此外，我认为没有必要将loginDate和expiryDate转换为Date，因为parse已经返回Date对象。

解析后，SimpleDateFormat提供错误的输出

3 个答案: