Question

lead table

lead_id  |   name    |  mobile
3710        aaa         888888
3713        bbb         777777
3714        ccc         666666

user table

user_id  |   email    |  pass   |  lead_id
38          ppp         *****       3710
39          qqq         *****       3713
40          rrr         *****       3710

History table

h_id | lead_id  | status  | user_id

49          3710         not dobale      38
108         3713         doable        38
109         3714         pipeline      38
110         3710         converted      38
111         3715         Login          38
112         3713         converted      38

我想不计算相关的lead_id的个人状态。

怎么做？

但对于lead_id 3710，必须考虑h_id 110而不是49意味着更高的h_id在lead_id 3713的情况下相同

输出应该是这样的：

ouput (for user_id 38)

status            No
converted   -     2   (lead_id is different)
pipeline       -  1
login      -      1

Answer 1

试试这个：

SELECT h.status, COUNT(DISTINCT lead_id)
FROM History h 
INNER JOIN (SELECT user_id, lead_id, MAX(h_id) h_id 
            FROM History 
            GROUP BY user_id, lead_id
          ) AS a ON h.user_id = a.user_id AND h.lead_id = a.lead_id AND h.h_id = a.h_id 
WHERE h.user_id = 38
GROUP BY h.status

Answer 2

因此，您需要从历史记录表中计算最新状态。您可以通过加入聚合来获得此结果，然后再次聚合。或者您可以使用substring_index() / group_concat()技巧：

select last_status, count(*)
from (select h.lead_id, substring_index(group_concat(status order by h_id desc), ',', 1) as last_status
      from history
      group by h.lead_id
     ) h
group by last_status;

如何计算历史表中每个状态的数字，请参阅输出

2 个答案: