Question

我正在建立一个消息系统，我必须获取消息，这是我的代码

我的ajax代码来获取结果 -

function fetch_conversation() {
    $.ajax({
        type: 'post',
        url: 'message_function.php',
        data: {
            fetch_conversation:'conversation'
        },
        success: function (response) {
            var r = $.parseJSON(response);
            alert(r.nno);
            alert(r.mmessage_from);
        }
    });
}

这是我的PHP代码，它获取数据并将其作为响应发送到ajax -

if(isset($_POST['fetch_conversation'])) {
    $select_message=mysql_query("select no,message_from,sent_time,message_body from    messages where message_to='1'  and sent_time > '2014-12-02 17:43:35' union select   no,message_to,sent_time,message_body from messages where message_from='1' and sent_time >   '2014-12-02 17:43:35' ")or die(mysql_error());

    while($row=mysql_fetch_array($select_message)) {
        $nno= $row['no'];
        echo json_encode($nno);
        $mmessage_from=$row['message_from'];
        echo json_encode($mmessage_from);
    }

    exit();
}

我使用的查询获取超过1行，我的问题是json无法返回获取对话函数中的值，如果查询只获取1行，则json显示所有值，所有警报都可见。如何使我的获取会话功能可以获得超过1行并显示警报，请任何帮助将不胜感激，也请尝试给出跨浏览器的代码谢谢....

Answer 1

**in the mesage_function.php file**

if(isset($_POST['fetch_conversation'])) {
    $select_message=mysql_query("select no,message_from,sent_time,message_body from    messages where message_to='1'  and sent_time > '2014-12-02 17:43:35' union select   no,message_to,sent_time,message_body from messages where message_from='1' and sent_time >   '2014-12-02 17:43:35' ")or die(mysql_error());
    $array = array();
    $i = 0;
    while($row=mysql_fetch_array($select_message)) {
        $array[$i]['no']= $row['no'];
        $array[$i]['mmessage_from']=$row['message_from'];
        $i++;
   }
   echo json_encode($array);
}   

**and in the ajax sucess alert only response and check log**

**try this, i hope this help.**

在您的成功回复中使用此代码将此代码放在parsejson之后添加你的表ID就在这里。

#add_your_id_here

function fetch_conversation()
 {
      $.ajax({
        type: 'post',
        url: 'message_function.php',
        data: {
            fetch_conversation:'conversation'
        },
        success: function (response) {

            var r = JSON.parse(response);
                var text = "";
                var x;
                for (x in r) {
                    $('#add_your_id_here').append('<tr><td>'+r[x]['mmessage_from']+'</td><td>'+r[x]['no']+'</td></tr>');

                }
            }
        });
 }

Answer 2

你能得到所有结果：

console.log(r);

你可以尝试

$.each(r, function(k, row) {
    alert(row.nno);
    alert(row.mmessage_from);
}

Answer 3

试试这个，

   function fetch_conversation()
   {
  $.ajax({
    type: 'post',
    dataType: 'json',
    url: 'message_function.php',
    data: {
    fetch_conversation:'conversation'
    },
    success: function (response) {

    var msg_no=response['no'];
    var msg_from=response['message_from'];

    alert(msg_no);
    alert(msg_from);
    }
    });
  }

和你的php

if(isset($_POST['fetch_conversation']))
 {
  $select_message=mysql_query("select no,message_from,sent_time,message_body from       messages where message_to='1'  and sent_time > '2014-12-02 17:43:35' union select   no,message_to,sent_time,message_body from messages where message_from='1' and sent_time >   '2014-12-02 17:43:35' ")or die(mysql_error());
 while($row=mysql_fetch_array($select_message))
 {
  $nno[]= $row['no'];

  $mmessage_from[]=$row['message_from'];

  }
  $arr['no']=$nno;
  $arr['message_from']=$mmessage_from;

   echo json_encode($arr);
 exit();
 }

Answer 4

 if(isset($_POST['fetch_conversation']))
 {
    $select_message = mysql_query("SELECT no,message_from,sent_time,message_body 
                                   FROM  messages WHERE message_to='1'  
                                   AND sent_time > '2014-12-02 17:43:35' 
                                   UNION 
                                   SELECT no,message_to,sent_time,message_body 
                                   FROM messages WHERE message_from='1' AND sent_time > '2014-12-02 17:43:35' ") or die(mysql_error());
     // create a result array to send response
     $result = array();   
     while($row=mysql_fetch_array($select_message))
     {
        $_temp = array();
        $_temp['no'] = $row['no'];
        $_temp['message_from'] = $row['message_from'];
        $result[] = $_temp;
        unset($_temp);
     }
     @header("Content-Type:text/json");
     echo json_encode($result);
     exit;
 }

请尝试使用上面的代码。这将为您提供由多个数组记录创建的json。您的html代码请按@Ferret建议。

如何使用json通过ajax响应获得超过1个结果

4 个答案: